We let x be the variable that when 17% is multiply by x it will equal 51.
Convert 17% decimal. To do this, move the % sign two places to the left and make it into a decimal point.
17% = 0.17
Now make our equation 0.17 * x = 51
Divide both sides by 0.17.
x = 300
In this question, we're trying to find how many miles Sophie can drive in an hour.
We know that she drove 162 miles in 3 hours.
With the information above, we can find our answer.
We need to see how much she drives in 1 hour, so you would divide 162 by 3.
162 ÷ 3 = 54
This means that she drives 54 mph.
Answer:
54 mph
The answer is the mean, mode, and median increases by 4, the range of times is the same.
Week 1: Week 2:
Student - Hours Student - Hours<span>
Bob 19 </span>Bob 23<span>
James 10 </span>James 14<span>
Karen 15 </span>Karen 19<span>
Rosario 17 </span>Rosario 21<span>
Antoine 10 </span>Antoine 14<span>
Julio 16 </span>Julio 20<span>
Maria 13 </span>Maria 17<span>
The mean is the sum of all values divided by the number of values:
Week 1: (19 + 10 + 15 + 17 + 10 + 16 + 13)/7 = 100/7 = 14.28
Week 2: (23 + 14 + 19 + 21 + 14 + 20 + 17)/7 = 128/7 = 18.28
The difference in means between Week 2 and Week 1 is 4 (18.28 - 14.28 = 4)
The median is the middle value. To calculate, first rearrange values from the lowest to the highest and then find the middle value:
Week 1: 10, 10, 13, 15, 16, 17, 19 - The median is 15.
Week 2: 14, 14, 17, 19, 20, 21, 23 - The median is 19.
The difference in medians between Week 2 and Week 1 is 4 (19 - 15 = 4)
The mode is the value that occurs most frequently.
</span>Week 1: 10, 10, 13, 15, 16, 17, 19 - The mode is 10.
Week 2: 14, 14, 17, 19, 20, 21, 23 - The mode is 14.
The difference in modes between Week 2 and Week 1 is 4 (14 - 10 = 4)
The range of times is the difference between the highest and the lowest value.
Week 1: 10, 10, 13, 15, 16, 17, 19 - The range of times is 9 (19 - 10 = 9).
Week 2: 14, 14, 17, 19, 20, 21, 23 - The median is 9 (23 - 14 = 9).
The difference in the ranges of times between Week 2 and Week 1 is 0 (9 - 9 = 0)
Answer:
550 N
Step-by-step explanation:
We can solve the problem by using Newton's second law:
F is the force required to accelerate the car
m is the mass of the car
a is the acceleration of the car
In this problem, the mass is m=1100 kg, while the acceleration is a=0.5 m/s^2, therefore the force required to accelerate the car is
Hope this helps!
