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3 years ago

13

Already bought 854 acres of land for development if 62 acres of his purchase is reserved for a park how many 3 acres building lo

ts are able for sale

1 answer:

TiliK225 [7]3 years ago

7 0

Take 854 - 62 = 792
then 792 ÷ 3 = 264

Final answer : 264

You might be interested in

Find the directional derivative of the function at the given point in the direction of the vector v. f(x, y, z) = xe^y + ye^z +

LUCKY_DIMON [66]

Answer:

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}$

Step-by-step explanation:

We need to find the directional derivative of the function at the given point in the direction of the vector v.

$f(x, y, z)=xe^{y} + ye^{z} + ze^{x}$ ,point (0, 0, 0) and $v=$

By Theorem: If f is a differentiable function of x , y and z , then f has a directional derivative for any unit vector $\overrightarrow{v} =$ and

$D_{\overrightarrow{u}}f(x,y,z)=f_{x}(x,y,z)u_1+f_{y}(x,y,z)u_2+f_{z}(x,y,z)u_3$

where $\overrightarrow{u}=\frac{\overrightarrow{v}}{||v||}$

since, $v=$

then $\overrightarrow{u}=\frac{\overrightarrow{v}}{||v||}$

$\overrightarrow{u}=< \frac{6}{\sqrt{6^{2}+3^{2}+(-3)^{2}}},\frac{3}{\sqrt{6^{2}+3^{2}+(-3)^{2}}},\frac{-3}{\sqrt{6^{2}+3^{2}+(-3)^{2}}} >$

$\overrightarrow{u}=< \frac{6}{\sqrt{54}},\frac{3}{\sqrt{54}},\frac{-3}{\sqrt{54}} >$

The partial derivatives are

$f_{x}(x,y,z)=e^{y}+ze^{x}$

$f_{y}(x,y,z)=xe^{y}+e^{z}$

$f_{z}(x,y,z)=ye^{z}+e^{x}$

Then the directional derivative is

$D_{\vec{u}}f(x,y,z)=(e^{y}+ze^{x})(\frac{6}{\sqrt{54}})+(xe^{y}+e^{z})(\frac{3}{\sqrt{54}})+(ye^{z}+e^{x})(\frac{-3}{\sqrt{54}})$

so, directional derivative at point (0,0,0)

$D_{\vec{u}}f(0,0,0)=(e^{0}+0e^{0})(\frac{6}{\sqrt{54}})+(0e^{0}+e^{0})(\frac{3}{\sqrt{54}})+(0e^{0}+e^{0})(\frac{-3}{\sqrt{54}})$

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}+\frac{3}{\sqrt{54}}+\frac{-3}{\sqrt{54}}$

$D_{\vec{u}}f(0,0,0)=\frac{6+3-3}{\sqrt{54}}$

$D_{\vec{u}}f(0,0,0)=\frac{6}{\sqrt{54}}$

3 0

4 years ago

5/6+1/4 these are fractions

Papessa [141]

5/6 + 1/4

multiply the denominators and numerators in order for equation to have the same denominators to help solve.

20/24 + 6/24

= 26/24

= 13/12

Hope you find this helpful!
Brainliest and a like is much appreciated!

3 0

3 years ago

estimate the sum or difference. 4/5+3/7, round 4/5 to its closest benchmark. round 3/7 to its closest benchmark. add to find the

Ann [662]

Answer:

About 1.5

Step-by-step explanation:

We can round 4/5 to 1.

We can round 3/8 to 4/8 = 1/2.

So our estimate is

4/5 + 3/8 =

about 1 + 1/2 = 1.5

(Shh... let's check using the calculator... it's 1.2. We were pretty close!)

7 0

3 years ago

B) Then solve for x given that the area of the shaded region is 48 square units. Show all your work

nasty-shy [4]

Answer:

10

Step-by-step explanation:

Here it's given that the area of the shaded region is 48 u² and we need to find out the value of x .

The given figure is made up of two rectangles where the smaller one is inscribed into the bigger one .

The area of shaded region will be equal to the difference of the areas of the two rectangles , that is equal to 48 u² .
The area of rectangle is length × breadth .
The dimensions of bigger rectangle is (x+3)(x-4) and that of smaller one is 3 × x .

So that ,

$\longrightarrow$ ar(bigger) - ar(smaller) = 48

$\longrightarrow$ [ (x+3) (x-4)] - 3(x) = 48

$\longrightarrow$ [ x² - 4x +3x -12 - 3x ] = 48

$\longrightarrow$ x² -4x -12 -48 = 0

$\longrightarrow$ x² - 4x - 60 = 0

$\longrightarrow$ x² - 10x + 4x - 60 = 0

$\longrightarrow$ x( x -10) +4(x -10) = 0

$\longrightarrow$ (x +4)(x-10) = 0

$\longrightarrow$ x = -4,10

Since sides can't be negative ,

$\longrightarrow$ x = 10

<h3>Hence the required answer is 10.</h3>

8 0

3 years ago

Many elementary school students in a school district currently have ear infections. A random sample of children in two different

Marta_Voda [28]

Answer:

Step-by-step explanation:

The summary of the given data includes;

sample size for the first school $n_1$ = 42

sample size for the second school $n_2$ = 34

so 16 out of 42 i.e $x_1$ = 16 and 18 out of 34 i.e $x_2$ = 18 have ear infection.

the proportion of students with ear infection Is as follows:

$\hat p_1 = \dfrac{16}{42}$ = 0.38095

$\hat p_2 = \dfrac{18}{34}$ = 0.5294

Since this is a two tailed test , the null and the alternative hypothesis can be computed as :

$H_0 :p_1 -p_2 = 0 \\ \\ H_1 : p_1 - p_2 \neq 0$

level of significance ∝ = 0.05,

Using the table of standard normal distribution, the value of z that corresponds to the two-tailed probability 0.05 is 1.96. Thus, we will reject the null hypothesis if the value of the test statistics is less than -1.96 or more than 1.96.

The test statistics for the difference in proportion can be achieved by using a pooled sample proportion.

$\bar p = \dfrac{x_1 +x_2}{n_1 +n_2}$

$\bar p = \dfrac{16 +18}{42 +34}$

$\bar p = \dfrac{34}{76}$

$\bar p = 0.447368$

$\bar p + \bar q = 1 \\ \\ \bar q = 1 -\bar p \\ \\\bar q = 1 - 0.447368 \\ \\\bar q = 0.552632$

The pooled standard error can be computed by using the formula:

$S.E = \sqrt{ \dfrac{ \bar p \bar q}{ n_1} + \dfrac{\bar p \bar p}{n_2} }$

$S.E = \sqrt{ \dfrac{ 0.447368 * 0.552632}{ 42} + \dfrac{ 0.447368 * 0.447368}{34} }$

$S.E = \sqrt{ \dfrac{ 0.2472298726}{ 42} + \dfrac{ 0.2001381274}{34} }$

$S.E = \sqrt{ 0.01177284105}$

$S.E = 0.1085$

The test statistics is ;

$z = \dfrac{\hat p_1 - \hat p_2}{S.E}$

$z = \dfrac{0.38095- 0.5294}{0.1085}$

$z = \dfrac{-0.14845}{0.1085}$

z = - 1.368

Decision Rule: Since the test statistics is greater than the rejection region - 1.96 , we fail to reject the null hypothesis.

Conclusion: There is insufficient evidence to support the claim that a difference exists between the proportions of students who have ear infections at the two schools

5 0

3 years ago