Parallel = same slope
Y = 1/5x + b
Plug in point
-8 = 1/5(-10) + b
-8 = -2 + b, b = -6
Equation: y = 1/5x - 6
Answer:
y = -1/2x +6
Step-by-step explanation:
We can use the slope intercept form of a line
y = mx+b where m is the slope and b is the y intercept
y = -1/2x +b
Substitute the point into the equation
9 = -1/2 (-6) +b
9 = 3+b
9-3 =b
6 =b
y = -1/2x +6
Answer:
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Answer:
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Step-by-step explanation:
With
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we have
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The vector field evaluated over this parameterization is

so the line integral is

