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d1i1m1o1n [39]
4 years ago
9

A special mixed-nut blend at a store cost $1.35 per lb, and in 2010 the blend cost $1.83 per lb. Let y represent the cost of a p

ound of the mixed-nut blend x years after 2005. Use a linear equation model to estimate the cost of a pound of the mixed-nut blend in 2007.
Mathematics
1 answer:
sashaice [31]4 years ago
3 0

Answer:

y = $1.542 per lb

Step-by-step explanation:

given data

mixed-nut blend store cost  2005 = $1.35 per lb

blend cost in 2010 = $1.83 per lb

solution

we consider here y = cost of a pound

and x year = after 2005

we will use here linear equation model

so

\frac{y - 1.35}{1.83-1.35} = \frac{x-10}{5 - 0}    .........................1

solve it we get

5y - 6.75 = .48 x

so

at 2007 year here x wil be 2

so

y = \frac{0.48 \times 2 + 6.75}{5}  

solve it we get

y = $1.542 per lb

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Answer:14/15

Step-by-step explanation:

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3 years ago
1-58. Mr. Wright was making a table to figure out how much it costs to send a certain numt
Drupady [299]

A table of values can be used to represent variables that are directly proportional.

The complete table of proportions is:

\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]

Given that

\left[\begin{array}{ccccccccc}Letters&10&2&[\ ]&7&1&500&[\ ] \\Cost&0.45&0.90&6.75&[\ ]&[\ ]&[\ ] & 18.90\end{array}\right]

Let:

<em />L \to<em> Letters</em>

<em />C \to<em> Cost</em>

<em />

Using proportional reasoning, we have:

C  = kL

Where

<em />k \to<em> ratio of proportion</em>

For the first values of C and L, we have:

C  = kL

0.45 = k \times 10

Divide both sides by 10

k = 0.045

So, the equation of proportion is:

C = 0.045L

<u>When C = 6.75, we have:</u>

C = 0.045L

6.75 = 0.045L

Solve for L

L = \frac{6.75}{0.045}

L = 150

<u>When L = 7, we have:</u>

C = 0.045L

C = 0.045 \times 7

C = 0.315

<u>When L = 1, we have:</u>

C = 0.045L

C = 0.045 \times 1

C = 0.045

<u>When L = 500, we have:</u>

C =0.045L\\

C =0.045 \times 500

C =22.5

<u>When C = 18.90, we have:</u>

C = 0.045L

18.90 = 0.045L

Solve for L

L=\frac{18.90}{0.045}

L=420

Hence, the complete table is:

\left[\begin{array}{ccccccccc}Letters&10&2&[150 ]&7&1&500&[420] \\Cost&0.45&0.90&6.75&[0.315]&[0.045 ]&[22.5 ] & 18.90\end{array}\right]

Read more about proportions at:

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3 years ago
1. Howard's CD House sells new CDs for $15 each and used CDs for $6 each. Bre'anna bought 51 CDs and spent a
Yanka [14]

The numbers of new CDs is 30 and the old CDs is 21.

To solve this problem, we have to write a system of equations in which we would know the numbers of each types of CD she bought.

<h3>System of Equations</h3>

This is used to solve a series or complex of word problems in which we can represent in a mathematical statements;

  • Let n represents numbers of new CDs
  • Let u represents numbers of old CDs

The equations can be represented as

n + u = 51 ...equation(i)\\15n + 6u = 576 ... equation(ii)

Let's take equation (i)

Making n the subject of formula

n + u = 51\\n = 51 - u...equation(iii)

we can put equation (iii) into equation (ii)

15n + 6u =576\\n = 51 - u\\15(51 - u) + 6u = 576\\765-15u + 6u = 576\\collect like terms\\765-576=15u - 6u\\189=9u\\9u/9 = 189/9\\u = 21

Let's put the value of u into equation (i)

n + u = 51\\u = 21\\n + 21 = 51\\n = 51 - 21\\n = 30

From the calculations above, the numbers of new CDs is 30 and the old CDs is 21.

Learn more on system of equations here;

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3 years ago
A whole number is 6 more than 2 times another number. The sum of the two numbers is less than 50. This can be written in an ineq
alukav5142 [94]

Answer:

13, 14

Step-by-step explanation:

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The sum of the two numbers is less than 50

Given that the first number is equal to more than twice the second number, we have that the first number is the larger number, while the second number is the smaller number

Where 'x' represents the second number, we get;

x + 2·x + 6 < 50

Simplifying gives;

3·x + 6 < 50

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x < 14.\overline 6

Therefore, the numbers for which the inequality holds true are numbers less than 14.\overline 6. From the given option, the numbers are 13, and 14.

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Blababa [14]

Answer:

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Step-by-step explanation:

Given:

P(A)=\frac{4}{7}

P(B|A)=\frac{3}{8}

We know that, conditional probability of B given that A has occurred is given as:

P(B|A)=\frac{P(A\cap B}{P(A)}. Expressing this in terms of P(A\cap B), we get

P(A\cap B)=P(B|A)\times P(A)

Plug in the known values and solve for P(A\cap B). This gives,

P(A\cap B)=P(B|A)\times P(A)\\P(A\cap B)=\frac{3}{8}\times \frac{4}{7}\\P(A\cap B)=\frac{12}{56}=\frac{3}{14}

Therefore, the probability of events A and B occurring is \frac{3}{14}.

6 0
3 years ago
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