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3 years ago

What is the equation of a line (in slope-intercept form) with a slope of -1 and a y

Mathematics

1 answer:

crimeas [40]3 years ago

6 0

Remember that the slope intercept formula is:

y = mx + b

m is the slope

b is the y-intercept

What we know:

slope: -1

y-intercept: 0.7

Therefore:

m = -1

b = 0.7

Plug the values of <em>m </em>and <em>b </em>in y = mx + b:

y = -1x + 0.7

y = -x + 0.7

y = 0.7 - x

^^^These are all written in slope intercept form but just in different ways

Hope this helped!

~Just a girl in love with Shawn Mendes

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Can someone help me with this math work and please explain why the answer is what it is

Anettt [7]

Answer: 58unit²

Step-by-step explanation:

We will take 1 square as 1 unit

We will count the number of squares in in this figure.

Total squares = 58

Area = 58unit²

please click thanks and mark brainliest if you like :)

4 0

2 years ago

Given: PRST is a square

xxTIMURxx [149]

Answer:

$(1-\sqrt{2})a^2$

Step-by-step explanation:

Consider irght triangle PRS. By the Pythagorean theorem,

$PS^2=PR^2+RS^2\\ \\PS^2=a^2+a^2\\ \\PS^2=2a^2\\ \\PS=\sqrt{2}a$

Thus,

$MS=PS-PM=\sqrt{2}a-a=(\sqrt{2}-1)a$

Consider isosceles triangle MSC. In this triangle

$MS=MC=(\sqrt{2}-1)a.$

The area of this triangle is

$A_{MSC}=\dfrac{1}{2}MS\cdot MC=\dfrac{1}{2}\cdot (\sqrt{2}-1)a\cdot (\sqrt{2}-1)a=\dfrac{(\sqrt{2}-1)^2a^2}{2}=\dfrac{(3-2\sqrt{2})a^2}{2}$

Consider right triangle PTS. The area of this triangle is

$A_{PTS}=\dfrac{1}{2}PT\cdot TS=\dfrac{1}{2}a\cdot a=\dfrac{a^2}{2}$

The area of the quadrilateral PMCT is the difference in area of triangles PTS and MSC:

$A_{PMCT}=\dfrac{(3-2\sqrt{2})a^2}{2}-\dfrac{a^2}{2}=\dfrac{(2-2\sqrt{2})a^2}{2}=(1-\sqrt{2})a^2$

5 0

3 years ago

Can someone Help me please?? :(

Sever21 [200]

Answer:

its 55

Step-by-step explanation:cuz why not

5 0

2 years ago

Read 2 more answers

Need help with math problem give 5 stars and brain thingy point

rewona [7]

Answer:

b) 2/6

Step-by-step explanation:

0, 1/6, 2/6, 3/6, 4/6, 5/6, 1

Hope this helps!

4 0

1 year ago

PLEASE HELP!!

Elena-2011 [213]

For this case we have the following equation:
S = 0.159 + 0.118logD
Substituting S = 0.2 we have:
0.2 = 0.159 + 0.118logD
From here, we clear the value of D.
We have then:
0.2 - 0.159 = 0.118logD
logD = (0.2 - 0.159) / (0.118)
logD = 0.347457627
10 ^ (logD) = 10 ^ 0.347457627
D = 10 ^ (0.347457627)
D = 2.23 mm
Answer:
The average diameter, D, of the sand particles for a beach is:
D = 2.23 mm

5 0

2 years ago