Answer:
- The equation 2n = p should be 2p = n.
- The actual cost of the onions is $3.00 per pound.
- Potatoes cost $1.50 per pound.
Step-by-step explanation:
The wording "onions cost twice as much as potatoes" is understood to mean the cost per pound of onions (n) is equal to two times the cost per pound of potatoes (2p). Then the appropriate equation would be ...
2p = n
Then the solution is ...
6p +3(2p) = 18
12p = 18
p = 18/12 = 1.50
n = 2p = 2(1.50) = 3.00
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The equation should be 2p = n; onions cost $3.00 per pound; potatoes cost $1.50 per pound.
Answer:
![Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%204.97%20-%281.61%29%5E2%20%3D2.3779)
And the deviation would be:

Step-by-step explanation:
For this case we have the following distribution given:
X 0 1 2 3 4 5 6
P(X) 0.3 0.25 0.2 0.12 0.07 0.04 0.02
For this case we need to find first the expected value given by:

And replacing we got:

Now we can find the second moment given by:

And replacing we got:

And the variance would be given by:
![Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779](https://tex.z-dn.net/?f=%20Var%28X%29%20%3D%20E%28X%5E2%29%20-%5BE%28X%29%5D%5E2%20%3D%204.97%20-%281.61%29%5E2%20%3D2.3779)
And the deviation would be:

The GCF is 2
Pull out 2 from each number:
2(2n + 5)
Hope this helps!
Answer:
13 pears in the 21st bag
Step-by-step explanation:
mean = total number of pears/total number of bags
8 = x/21
x = 168
number of pears in 20 bags = (6 x 2) + (7 x 6) + (8 x 9) + (9 x 1) + (10 x 2)
= 155
number of pears in the 21st bag = 168 - 155
= 13