The area of D is given by:
The average value of f over D is given by:
![\frac{1}{ \frac{343}{3} } \int\limits^7_0 \int\limits^{x^2}_0 {4x\sin(y)} \, dydx = -\frac{3}{343} \int\limits^7_0 {4x\cos(x^2)} \, dx \\ \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49](https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B%20%5Cfrac%7B343%7D%7B3%7D%20%7D%20%20%5Cint%5Climits%5E7_0%20%20%5Cint%5Climits%5E%7Bx%5E2%7D_0%20%7B4x%5Csin%28y%29%7D%20%5C%2C%20dydx%20%20%3D%20-%5Cfrac%7B3%7D%7B343%7D%20%20%5Cint%5Climits%5E7_0%20%7B4x%5Ccos%28x%5E2%29%7D%20%5C%2C%20dx%20%20%5C%5C%20%20%5C%5C%20%3D-%5Cfrac%7B3%7D%7B343%7D%20%5Cint%5Climits%5E%7B49%7D_0%20%7B2%5Ccos%28t%29%7D%20%5C%2C%20dt%3D-%5Cfrac%7B6%7D%7B343%7D%20%5Cleft%5B%5Csin%28t%29%5Cright%5D_0%5E%7B49%7D%20%5C%2C%20dt%3D-%5Cfrac%7B6%7D%7B343%7D%5Csin49)
The average value of f over D is given by:
Neha used 4 bananas and 5 oranges in her fruit salad. Daniel used 7 bananas and 9 oranges. Did Neha and Daniel use the same rati
1 answer:
Answer:
<em>Neha and Daniel do not use the same ratio of bananas to oranges</em>
<em>Neha used the grater ratio of bananas to oranges</em>
Step-by-step explanation:
<u>Ratios</u>
The ratio is expressed as a:b, where a and b are whole numbers.
Neha used 4 bananas and 5 oranges in her fruit salad. Daniel used 7 bananas and 9 oranges in his.
We use cross multiplication to find if the ratios of bananas to oranges are the same.
Neha s ratio is 4:5
Daniel s ratio is 7:9
To compare both ratios we use the expression:
The question mark means equality could be true or false.
The cross multiplication consists of multiplying the denominator of one side by the numerator of the other side:
Operating:
The equality is false, thus
Neha and Daniel do not use the same ratio of bananas to oranges
Since the left side of the equality is greater than the second:
Neha used the grater ratio of bananas to oranges
You might be interested in
Answer:
Step-by-step explanation:
Hi there!
<u>What we need to know:</u>
- Linear equations are typically organized in slope-intercept form:
where m is the slope of the line and b is the y-intercept (the value of y when the line crosses the y-axis)
- Parallel lines will always have the same slope but different y-intercepts.
<u>1) Determine the slope of the parallel line</u>
Organize 3x = 2y into slope-intercept form. Why? So we can easily identify the slope, m.
Switch the sides
Divide both sides by 2 to isolate y
Now that this equation is in slope-intercept form, we can easily identify that is in the place of m. Therefore, because parallel lines have the same slope, the parallel line we're solving for now will also have the slope
. Plug this into
:
<u>2) Determine the y-intercept</u>
Plug in the given point, (4,0)
Subtract both sides by 6
Therefore, -6 is the y-intercept of the line. Plug this into as b:
I hope this helps!