Answer:
Q1) (x+7)² = 9
x = -10, -4
Q2) (x-8)² = 144
x = -4, 20
Q3) (x-1)² = 81
x = -8, 10
Step-by-step explanation:
Q1) x² + 14x + 49 = 9
x² + 2(x)(7) + 7² = 9
(x + 7)² = 9
x + 7 = +/- sqrt(9)
x + 7 = 3
x = -4
x + 7 = -3
x = -10
Q2) x² - 16x + 64 = 144
x² - 2(x)(8) + 8² = 144
(x - 8)² = 144
x - 8 = +/- sqrt(144)
x - 8 = 12
x = 20
x - 8 = -12
x = -4
Q3) x² - 2x + 1 = 81
x² - 2(x)(1) + 1² = 81
(x - 1)² = 81
x - 1 =+/- sqrt(81)
x - 1 = 9
x = 10
x - 1 = -9
x = -8
Answer:y=-2(x-1)-4
Step-by-step explanation:
you need to isolate Y. and 4 is in the same group on the plus so you move it by subtracting and adding a negative on the other side.
Answer:
49/81
Step-by-step explanation:
[cos(a) + sin(a)]^2 = (1/3)^2
(cos(a))^2 + 2sin(a)cos(a) + (sin(a))^2 = 1/9
(sin(a))^2 + (cos(a))^2 = 1
1 + 2sin(a)cos(a) = 1/9
2sin(a)cos(a) = -8/9
sin(a)cos(a) = -4/9
[cos(a) + sin(a)]^4 = (1/3)^4 = 1/81
(cos(a))^4 + 4sin(a)×(cos(a))^3 + 6×(sin(a))^2×(cos(a))^2 + 4(sin(a))^3×cos(a) + (sin(a))^4 = 1/81
(cos(a))^4 + (sin(a))^4 + 4sin(a)cos(a)((cos(a))^2 + (sin(a))^2) + 6(sin(a)cos(a))^2 = 1/81
cos(a))^4 + (sin(a))^4 + 4sin(a)cos(a)(1) + 6(sin(a)cos(a))^2 = 1/81
(cos(a))^4 + (sin(a))^4 + 4(-4/9) +6((-4/9)^2) = 1/81
(cos(a))^4 + (sin(a))^4 - 16/9 + 6(16/81) = 1/81
(cos(a))^4 + (sin(a))^4 = 1/81 + 16/9 - 6(16/81)
(cos(a))^4 + (sin(a))^4 = 49/81
Sub in what X and y are:
. Solve the exponents (if the exponent is 2 multiply the whole number by itself twice, if it were 3 you would multiply the whole number by itself three times): 3·3=9, 3·3=9: 9(9)= 81. :)
They each practice 6 days a week so yes. 14 days= 1 week You can then do this by taking 24/4=6 and 12/2= 6
