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3 years ago

ANSWER AND SHOW WORK FOR 40 POINTS

Mathematics

2 answers:

sergeinik [125]3 years ago

6 0

Answer: Q1) (x+7)² = 9

x = -10, -4

Q2) (x-8)² = 144

x = -4, 20

Q3) (x-1)² = 81

x = -8, 10

Step-by-step explanation:

Q1) x² + 14x + 49 = 9

x² + 2(x)(7) + 7² = 9

(x + 7)² = 9

x + 7 = +/- sqrt(9)

x + 7 = 3

x = -4

x + 7 = -3

x = -10

Q2) x² - 16x + 64 = 144

x² - 2(x)(8) + 8² = 144

(x - 8)² = 144

x - 8 = +/- sqrt(144)

x - 8 = 12

x = 20

x - 8 = -12

x = -4

Q3) x² - 2x + 1 = 81

x² - 2(x)(1) + 1² = 81

(x - 1)² = 81

x - 1 =+/- sqrt(81)

x - 1 = 9

x = 10

x - 1 = -9

x = -8

Step-by-step explanation:

Elanso [62]3 years ago

5 0

Answer:

Q1) (x+7)² = 9

x = -10, -4

Q2) (x-8)² = 144

x = -4, 20

Q3) (x-1)² = 81

x = -8, 10

Step-by-step explanation:

Q1) x² + 14x + 49 = 9

x² + 2(x)(7) + 7² = 9

(x + 7)² = 9

x + 7 = +/- sqrt(9)

x + 7 = 3

x = -4

x + 7 = -3

x = -10

Q2) x² - 16x + 64 = 144

x² - 2(x)(8) + 8² = 144

(x - 8)² = 144

x - 8 = +/- sqrt(144)

x - 8 = 12

x = 20

x - 8 = -12

x = -4

Q3) x² - 2x + 1 = 81

x² - 2(x)(1) + 1² = 81

(x - 1)² = 81

x - 1 =+/- sqrt(81)

x - 1 = 9

x = 10

x - 1 = -9

x = -8

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A fast food restaurant executive wishes to know how many fast food meals teenagers eat each week. They want to construct a 99% c

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Answer:

The minimum sample size required to create the specified confidence interval is 2229.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

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Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

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Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when $M = 0.06, \sigma = 1.1$

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$0.06\sqrt{n} = 2.575*1.1$

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Rounding up

The minimum sample size required to create the specified confidence interval is 2229.

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3 years ago

A cylinder has a radius of 14 m and a height of 6 m.

Irina18 [472]

Volume of the cylinder is 3696 m²

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3 years ago

Activity 4: Performance Task

Nookie1986 [14]

An arithmetic progression is simply a progression with a common difference among consecutive terms.

The sum of multiplies of 6 between 8 and 70 is 390
The sum of multiplies of 5 between 12 and 92 is 840
The sum of multiplies of 3 between 1 and 50 is 408
The sum of multiplies of 11 between 10 and 122 is 726
The sum of multiplies of 9 between 25 and 100 is 567
The sum of the first 20 terms is 630
The sum of the first 15 terms is 480
The sum of the first 32 terms is 3136
The sum of the first 27 terms is -486
The sum of the first 51 terms is 2193

(a) Sum of multiples of 6, between 8 and 70

There are 10 multiples of 6 between 8 and 70, and the first of them is 12.

This means that:

$\mathbf{a = 12}$

$\mathbf{n = 10}$

$\mathbf{d = 6}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{10} = \frac{10}2(2*12 + (10 - 1)6)}$

$\mathbf{S_{10} = 390}$

(b) Multiples of 5 between 12 and 92

There are 16 multiples of 5 between 12 and 92, and the first of them is 15.

This means that:

$\mathbf{a = 15}$

$\mathbf{n = 16}$

$\mathbf{d = 5}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{16}2(2*15 + (16 - 1)5)}$

$\mathbf{S_{16} = 840}$

(c) Multiples of 3 between 1 and 50

There are 16 multiples of 3 between 1 and 50, and the first of them is 3.

This means that:

$\mathbf{a = 3}$

$\mathbf{n = 16}$

$\mathbf{d = 3}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{16}2(2*3 + (16 - 1)3)}$

$\mathbf{S_{16} = 408}$

(d) Multiples of 11 between 10 and 122

There are 11 multiples of 11 between 10 and 122, and the first of them is 11.

This means that:

$\mathbf{a = 11}$

$\mathbf{n = 11}$

$\mathbf{d = 11}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{16} = \frac{11}2(2*11 + (11 - 1)11)}$

$\mathbf{S_{11} = 726}$

(e) Multiples of 9 between 25 and 100

There are 9 multiples of 9 between 25 and 100, and the first of them is 27.

This means that:

$\mathbf{a = 27}$

$\mathbf{n = 9}$

$\mathbf{d = 9}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{9} = \frac{9}2(2*27 + (9 - 1)9)}$

$\mathbf{S_{9} = 567}$

(f) Sum of first 20 terms

The given parameters are:

$\mathbf{a = 3}$

$\mathbf{d = 3}$

$\mathbf{n = 20}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{20} = \frac{20}2(2*3 + (20 - 1)3)}$

$\mathbf{S_{20} = 630}$

(f) Sum of first 15 terms

The given parameters are:

$\mathbf{a = 4}$

$\mathbf{d = 4}$

$\mathbf{n = 15}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{15} = \frac{15}2(2*4 + (15 - 1)4)}$

$\mathbf{S_{15} = 480}$

(g) Sum of first 32 terms

The given parameters are:

$\mathbf{a = 5}$

$\mathbf{d = 6}$

$\mathbf{n = 32}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{32} = \frac{32}2(2*5 + (32 - 1)6)}$

$\mathbf{S_{32} = 3136}$

(g) Sum of first 27 terms

The given parameters are:

$\mathbf{a = 8}$

$\mathbf{d = -2}$

$\mathbf{n = 27}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{27} = \frac{27}2(2*8 + (27 - 1)*-2)}$

$\mathbf{S_{27} = -486}$

(h) Sum of first 51 terms

The given parameters are:

$\mathbf{a = -7}$

$\mathbf{d = 2}$

$\mathbf{n = 51}$

The sum of n terms of an AP is:

$\mathbf{S_n = \frac n2(2a + (n - 1)d)}$

Substitute known values

$\mathbf{S_{51} = \frac{51}2(2*-7 + (51 - 1)*2)}$

$\mathbf{S_{51} = 2193}$

Read more about arithmetic progressions at:

brainly.com/question/13989292

4 0

2 years ago

Read 2 more answers

What is 9x9x9x9x9x9x9x9x9x9x9x9x9x9x8? Will upvote!

n200080 [17]

IDK vhruvurvjrnedyjjnryghtfjdhvujrnhbyufj

4 0

3 years ago