Answer:
B. .007
Step-by-step explanation:
Mean=μ=23500
Standard deviation=σ=7200
For sample of 50 students
Mean=μxbar=μx=23500
Standard deviation=σxbar=σ/√n=7200/√50=1018.23
So, the probability that mean outstanding loan for students is under $21000
P(xbar<21000)=P((xbar-μxbar)/σxbar<(21000-23500)/1018.23)=P(Z<-2.455)
P(xbar<21000)=P(Z<-2.455)
P(xbar<21000)=P(-∞<z<0)-P(0<z<-2.455)
P(xbar<21000)=0.5-0.4930=0.007
Thus, the probability that mean outstanding loan for students is under $21000 is 0.007.
Am sorry i was unable to show you my calculations but my answer is 115.5 for 20%and for full tank costs 592.5
Answer:
46.25%
Step-by-step explanation:
First, add both numbers together. (86 + 74).
Next, we have 160. And that is 100%.
Now, we have to find what 74 is compared to 160.
74 is 46.25% of 160.
There's our answer.
Let's say b equals 2
2^4=16
16*2= 32
This is what I could make of the question
Answer:
8.275
Step-by-step explanation:
8.280 - 8.270 = 0.010
0.010/2 = 0.005
8.270 + 0.005 = 8.275