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slavikrds [6]
2 years ago
15

five times as many girls as boys went to the dance. The total of 120 students went to the dance. How many boys and girls went to

the dance?
Mathematics
1 answer:
ryzh [129]2 years ago
8 0

Answer:

100 girls and 20 boys

Step-by-step explanation:

since its 5 times as many girls multiply 20 by 5 which is 100 and then boom 20 boys cause 100 divided by 5 is 20

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What all numbers whose absolute value is 6
GalinKa [24]

Answer:

6, -6

Explanation:

-----

3 0
3 years ago
Find two power series solutions of the given differential equation about the ordinary point x = 0. compare the series solutions
monitta
I don't know what method is referred to in "section 4.3", but I'll suppose it's reduction of order and use that to find the exact solution. Take z=y', so that z'=y'' and we're left with the ODE linear in z:

y''-y'=0\implies z'-z=0\implies z=C_1e^x\implies y=C_1e^x+C_2

Now suppose y has a power series expansion

y=\displaystyle\sum_{n\ge0}a_nx^n
\implies y'=\displaystyle\sum_{n\ge1}na_nx^{n-1}
\implies y''=\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}

Then the ODE can be written as

\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge1}na_nx^{n-1}=0

\displaystyle\sum_{n\ge2}n(n-1)a_nx^{n-2}-\sum_{n\ge2}(n-1)a_{n-1}x^{n-2}=0

\displaystyle\sum_{n\ge2}\bigg[n(n-1)a_n-(n-1)a_{n-1}\bigg]x^{n-2}=0

All the coefficients of the series vanish, and setting x=0 in the power series forms for y and y' tell us that y(0)=a_0 and y'(0)=a_1, so we get the recurrence

\begin{cases}a_0=a_0\\\\a_1=a_1\\\\a_n=\dfrac{a_{n-1}}n&\text{for }n\ge2\end{cases}

We can solve explicitly for a_n quite easily:

a_n=\dfrac{a_{n-1}}n\implies a_{n-1}=\dfrac{a_{n-2}}{n-1}\implies a_n=\dfrac{a_{n-2}}{n(n-1)}

and so on. Continuing in this way we end up with

a_n=\dfrac{a_1}{n!}

so that the solution to the ODE is

y(x)=\displaystyle\sum_{n\ge0}\dfrac{a_1}{n!}x^n=a_1+a_1x+\dfrac{a_1}2x^2+\cdots=a_1e^x

We also require the solution to satisfy y(0)=a_0, which we can do easily by adding and subtracting a constant as needed:

y(x)=a_0-a_1+a_1+\displaystyle\sum_{n\ge1}\dfrac{a_1}{n!}x^n=\underbrace{a_0-a_1}_{C_2}+\underbrace{a_1}_{C_1}\displaystyle\sum_{n\ge0}\frac{x^n}{n!}
4 0
3 years ago
Mathhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhhh
kirill115 [55]

Question? i cant see again friend

8 0
2 years ago
I made 10 cups of granola that we eat in ⅔ cup servings. How many servings will we have out of the 10 cups of granola?
attashe74 [19]

Answer:

15 servings

Step-by-step explanation:

divide the numbers

3 0
3 years ago
What is the LCM of 3,5,7
Lubov Fominskaja [6]

Answer:

The least common multiple would be 105.

Step-by-step explanation:

You would do list out the multiples for each. Or multiply

Since 3 x 30 is 90, and 3 x 5  is 15, This is 105

And since 5 x 20 is 100, and 5 x 1 is 5, This is 105 as well

Also, since 7 x 10 is 70, and 7 x 5 is 35, This is 105.

The LCM is 105

Have a great Day!

4 0
3 years ago
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