Answer:
C
Step-by-step explanation:
hope this helps with the work
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Answer:
is this geomtey
Step-by-step explanation:
Make sure to put what kind of maths (geometry algebra ect.) this is so others can meet your needs better. Also might want to put what unit or type of problem this is as well.
Answer:
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Step-by-step explanation:
given that acceleration vector is a funciton of time and at time t

v(t) can be obtained by integrating a(t)
v(t) = 
Thus we use the fact that acceleration is derivative of velocity and velocity is antiderivative of acceleration.
The arbitary constant normally used for integration C is here C vector = initial velocity (u0,v0,w0)
Position vector can be obtained by integrating v(t)
Thus we find that velocity vector at time t is
(5t+15, 5t^2/2, 4t^2)
Answer:
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Step-by-step explanation: