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3 years ago

Please help me you guys

Mathematics

1 answer:

Neko [114]3 years ago

3 0

Answer:

g(x) = |x+3| - 5

Step-by-step explanation:

Let y = f(x)

⇒y = |x+3|

When y is replaced by Y + k, the graph of y = f(x) shifts k units down

⇒ y replaced by Y + 5 translates the graph of y = f(x) 5 units down

∴ Y = g(x) is represented by Y + 5 = |x+3|

⇒ Y = |x+3| - 5

or g(x) = |x+3| - 5

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A line contains the points (30, 1) and (39, 4). Find the slope of the line?

satela [25.4K]

Answer:

Rise/Run

4-1/39-30

3/9

1/3 Is the slope

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2 years ago

Read 2 more answers

A. 0.1925 B.0.1575 C.0.2925 D.0.3575 HELP PLEASE!!!

Elena-2011 [213]

A, because:

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3 0

3 years ago

A total of 815 tickets were sold for the school play. They were either adult tickets or student tickets. There were 65 more stud

kvv77 [185]

Answer:

375 Adult Tickets.

Step-by-step explanation:

Here, we can simply set up an equation using variable x in place of the unknown student/adult tickets.

x = # of adult tickets sold

x + 65 = # of student tickets sold.

1) x + x + 65 = 815 (set both ticket amounts equal to the total)

2) 2x + 65 = 815 (added common variables together)

3) 2x = 750 (negated the +65, subtracted it from both sides)

4) x = 375 (divided both sides by 2)

5) 815 - 375 = 440 (subtracted the x from the total number of adult tickets, to recieve the amount of childrens' tickets.

Therefore,

Since there were fewer adult tickets sold (-65), 375 is the number of adult tickets, and 440 is the number of student tickets.

5 0

2 years ago

Can someone please help me?

Nonamiya [84]

you have to read the bottom link for the answer key

3 0

2 years ago

Is the following statement correct? Explain.

Maksim231197 [3]

Answer: The answer is NO.

Step-by-step explanation: The given statement is -

If the graph of two equations are coincident lines, then that system of equations will have no solution.

We are to check whether the above statement is correct or not.

Any two equations having graphs as coincident lines are of the form -

$ax+by=c,\\\\dax+dby=dc,\\\\\textup{where}~~d\neq 1.$

If we take d = 1, then both the equations will be same.

Now, subtracting the second equation from first, we have

$a(1-d)x+b(1-d)y=c(1-d)\\\\\Rightarrow ax+by=c,~\textup{since}~d\neq 1,~\textup{so}~1-d\neq 0.$

Again, we will get the first equation, which is linear in two unknown variables. So, the system will have infinite number of solutions, which consists of the points lying on the line.

For example, see the attached figure, the graphs of following two equations is drawn and they are coincident. Also, the result is again the same straight line which has infinite number of points on it. These points makes the solution for the following system.

$2x+5y=10,\\\\6x+15y=30.$

Thus, the given statement is not correct.

4 0

3 years ago