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3 years ago

5

Carver is trying to reproduce a scale drawing where every 3 in. will be equal to 2 feet. How long should Carver make the red lin

e, in feet?

2 answers:

sdas [7]3 years ago

8 0

Answer:

6ft

Step-by-step explanation:

If the scale is 3in:2ft then every 3 inches is equal to 2 feet. 9in can be divided into 3 3in sections and after the sections are scaled 3 2t sections which in all are equal to 6ft.

lozanna [386]3 years ago

3 0

Answer:

6 ft

Step-by-step explanation:

Since the red line is 9 feet long, and we know that $3\cdot3 = 9$ , we can note that 3 inches goes into 9 inches 3 times.

Now that we are making the red line increase by 2 feet for every 3 inches, we can multiply the values.

2 feet × 3 times = 6 feet

So Carver should make the red line 6 feet long.

Hope this helped!

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Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

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Step-by-step explanation:

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Answer:

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