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Alika [10]
3 years ago
10

Lim (1 + 1/x)^(3x) as x->infinity

Mathematics
1 answer:
kobusy [5.1K]3 years ago
4 0
Lim ln([(x+1)/x]^3x) as x ->.infinity =lim ln([(x+1)^(3x)]/[x^(3x)]) as s->infinity =lim ln((x+1)^(3x))-ln(x^(3x)) = infinity - infinity
your answer is e3 but you can use l'hopital if you liketake the log, get 3xln(1+1/x)which is in the form ∞×0 then use the usual trick of rewriting as ln(1+1/x)/1/3x
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Mo and Jo Share Their "Dough" Mo and Jo each have a different amount of money. They only have dollar bills. If Mo gave Jo $10, t
Zinaida [17]

Answer:

Mo has $70, Jo has $50 and together they have $120.

Step-by-step explanation:

As the statement indicates that if Mo gave Jo $10, they would both have the same amount, you can say that you can subtract $10 from the money Mo has and that would be equal to the amount Jo has plus $10, which can be expressed as:

x-10=y+10 (1), where:

x is the amount of money Mo has

y is the amount of money Jo has

Also, the statement says that if Jo gave Mo $10, Mo would have twice as much money as Jo which means that if you add 10 to the money Mo has this would be equal to two times the money Jo has minus $10, which would be:

x+10=2(y-10) (2)

Now, you can isolate x in the first equation and then, replace that on the second one:

x=y+20

Now, you can replace this in 2 and solve for y:

x+10=2(y-10)

y+20+10=2y-20

30+20=2y-y

y=50

You can replace the value of y in x=y+20 in order to find the value of x:

x=50+20

x=70

Finally, you can add both amounts to find the amount of money they have altogether:

70+50=120

According to this, the answer is that: Mo has $70, Jo has $50 and together they have $120.

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The answer i got is:
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Answer:

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Step-by-step explanation:

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