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ser-zykov [4K]
3 years ago
12

What is 6.48 round to the nearest tenth

Mathematics
1 answer:
lawyer [7]3 years ago
8 0

Answer:

6.5

Step-by-step explanation:

To round 6.48 to nearest tenth means to round the numbers so you only have one digit in the fractional part.

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Answer:

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Step-by-step explanation:

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If your dogs heart rate is 90 times per minute how many times would it beat in an hour?​
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Answer:5400

Step-by-step explanation: 1 hour is 60 minutes, so 90 * 60 = 5400

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What is the first number in 6523÷7?
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931 is the frst number and the rest ar decimals ie 931.857142.......
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Choose the appropriate algebraic expression from the following verbal phrase: The quotient of y and the sum of x and 5.
bearhunter [10]
1/y + (x+5) Hope this helps!
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3 years ago
A tank contains 30 lb of salt dissolved in 300 gallons of water. a brine solution is pumped into the tank at a rate of 3 gal/min
sesenic [268]
A'(t)=(\text{flow rate in})(\text{inflow concentration})-(\text{flow rate out})(\text{outflow concentration})
\implies A'(t)=\dfrac{3\text{ gal}}{1\text{ min}}\cdot\left(2+\sin\dfrac t4\right)\dfrac{\text{lb}}{\text{gal}}-\dfrac{3\text{ gal}}{1\text{ min}}\cdot\dfrac{A(t)\text{ lb}}{300+(3-3)t\text{ gal}}
A'(t)+\dfrac1{100}A(t)=6+3\sin\dfrac t4

We're given that A(0)=30. Multiply both sides by the integrating factor e^{t/100}, then

e^{t/100}A'(t)+\dfrac1{100}e^{t/100}A(t)=6e^{t/100}+3e^{t/100}\sin\dfrac t4
\left(e^{t/100}A(t)\right)'=6e^{t/100}+3e^{t/100}\sin\dfrac t4
e^{t/100}A(t)=600e^{t/100}-\dfrac{150}{313}e^{t/100}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+C
A(t)=600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)+Ce^{-t/100}

Given that A(0)=30, we have

30=600-\dfrac{150}{313}\cdot25+C\implies C=-\dfrac{174660}{313}\approx-558.02

so the amount of salt in the tank at time t is

A(t)\approx600-\dfrac{150}{313}\left(25\cos\dfrac t4-\sin\dfrac t4\right)-558.02e^{-t/100}
3 0
3 years ago
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