The rate of the passenger train is 81.67 MPH and the rate of the freight train is 66.67 MPH.
<h3>What is a linear equation?</h3>
It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have:
The distance traveled by passenger train = 245 miles
The distance traveled by freight train = 245 miles
The time takes for both trains is the same.
Let's suppose the rate of the passenger train is x and the rate of the freight train is y;
As we know,
Distance = speed×time
245/x = 200/y
200x = 245y
200x - 245y = 0 ..(1)
x = 15 + y ..(2)
Equations (1) and (2) represent the situation.
After solving equations (1) and (2):

Thus, the rate of the passenger train is 81.67 MPH and the rate of the freight train is 66.67 MPH.
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Answer: x is the amount of orange juice they can buy. And y is the amount of money they have. Set y equal to 13.26 and solve the equation.
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Answer:
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Answer:
The 95% confidece estimate for how much a typical parent would spend on their child's birthday gift is between $37.47 and $46.53.
Step-by-step explanation:
The results were roughly normal, so we can find the normal confidence interval.
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find M as such

In which
is the standard deviation of the population and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 42 - 4.53 = $37.47.
The upper end of the interval is the sample mean added to M. So it is 42 + 4.53 = $46.53.
The 95% confidece estimate for how much a typical parent would spend on their child's birthday gift is between $37.47 and $46.53.
Answer:
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