Answer:
Question is in attached file
1 answer:
The rate of the passenger train is 81.67 MPH and the rate of the freight train is 66.67 MPH.
<h3>What is a linear equation?</h3>It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.
If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.
We have:
The distance traveled by passenger train = 245 miles
The distance traveled by freight train = 245 miles
The time takes for both trains is the same.
Let's suppose the rate of the passenger train is x and the rate of the freight train is y;
As we know,
Distance = speed×time
245/x = 200/y
200x = 245y
200x - 245y = 0 ..(1)
x = 15 + y ..(2)
Equations (1) and (2) represent the situation.
After solving equations (1) and (2):
Thus, the rate of the passenger train is 81.67 MPH and the rate of the freight train is 66.67 MPH.
Learn more about the linear equation here:
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Answer:
A
Step-by-step explanation:
There are two ways you could do this question. You could graph it with something like Desmos or you could put a couple of x values in for f(x). I'll do the latter first. When you understand it, try putting it into Desmos.
f(x) = (3/4)^x
f(0) = (3/4)^0
f(0) = 1
=======
f(x) = (3/4)^x
f(1) = 3/4
=========
g(x) = (3/4)^x - 6
g(0) = (3/4)^0 - 6
g(0) = 1 - 6
g(0) = - 5
========
g(x) = (3/4)^x - 6
g(1) = (3/4)^1 - 6
g(1)= 3/4 - 6
g(1) = -5 1/4
Conclusion
It looks like the graph has shifted down 6.
Answer
A
