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prisoha [69]
3 years ago
5

The average weight of the top 5 fish at a fishing tournament was 13.6 pounds. Some of the weights of the

Mathematics
1 answer:
lapo4ka [179]3 years ago
6 0

Answer:  Carla P.  15.1

Step-by-step explanation:

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Find the product of (x + 5)(x − 5). (1 point)
sleet_krkn [62]
FOIL (first outside inside last)

x^2-5x+5x-25 = x^2-25
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3 years ago
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Tom jogged from 10.30 to 12.15. He traveled 7 miles. What was his average rate of jogging?
maks197457 [2]
From 1030 to 1100 is 30 minutes
From 1100 to 1200 is 60 minutes
From 1200 to 1215 is 15 minutes
Total Time is 105 minutes
105/7=15
Tom completes 1 mile every 15 minutes
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4 years ago
What is the missing term? Please help me
matrenka [14]

Answer:

6x

Step-by-step explanation:

2x*3x=6x

4 0
3 years ago
Convert 22 to a numeral in base 2.
musickatia [10]
The answer is 10110

===============================================

Explanation:

Divide 22 over 2. Use long division to find the quotient and remainder
22/2 = 11 remainder 0 <<--- this remainder will be used later. Call it A, so A = 0

Now repeat for the value 11, which was the quotient above
11/2 = 5 remainder 1 <<--- this remainder will be used later. Call it B, so B = 1

Repeat again for the quotient we just got
5/2 = 2 remainder 1 <<--- this remainder will be used later. Call it C, so C = 1

Repeat again
2/2 = 1 remainder 0 <<--- this remainder will be used later. Call it D, so D = 0

Repeat again
1/2 = 0 remainder 1 <<--- this remainder will be used later. Call it E, so E = 1

The last quotient above is 0, so we stop here. If we tried to keep going, then we'd get nothing but 0 remainders forever.

The remainders we got above were:
A = 0
B = 1
C = 1
D = 0
E = 1

The idea is to read the remainders in reverse order in which we found. So we start with E and work back to A
E = 1
D = 0
C = 1
B = 1
A = 0

So 22 base 10 = 10110 base 2

5 0
3 years ago
Read 2 more answers
Find the direction cosines and direction angles of the vector. (Give the direction angles correct to the nearest degree.) 5, 1,
Dahasolnce [82]

Answer:

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

Step-by-step explanation:

For a given vector a = ai + aj + ak, its direction cosines are the cosines of the angles which it makes with the x, y and z axes.

If a makes angles α, β, and γ (which are the direction angles) with the x, y and z axes respectively, then its direction cosines are: cos α, cos β and cos γ in the x, y and z axes respectively.

Where;

cos α = \frac{a . i}{|a| . |i|}               ---------------------(i)

cos β = \frac{a.j}{|a||j|}               ---------------------(ii)

cos γ = \frac{a.k}{|a|.|k|}             ----------------------(iii)

<em>And from these we can get the direction angles as follows;</em>

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

Now to the question:

Let the given vector be

a = 5i + j + 4k

a . i =  (5i + j + 4k) . (i)

a . i = 5         [a.i <em>is just the x component of the vector</em>]

a . j = 1            [<em>the y component of the vector</em>]

a . k = 4          [<em>the z component of the vector</em>]

<em>Also</em>

|a|. |i| = |a|. |j| = |a|. |k| = |a|           [since |i| = |j| = |k| = 1]

|a| = \sqrt{5^2 + 1^2 + 4^2}

|a| = \sqrt{25 + 1 + 16}

|a| = \sqrt{42}

Now substitute these values into equations (i) - (iii) to get the direction cosines. i.e

cos α = \frac{5}{\sqrt{42} }

cos β =  \frac{1}{\sqrt{42} }              

cos γ =  \frac{4}{\sqrt{42} }

From the value, now find the direction angles as follows;

α =  cos⁻¹ ( \frac{a . i}{|a| . |i|} )

α =  cos⁻¹ ( \frac{5}{\sqrt{42} } )

α =  cos⁻¹ (\frac{5}{6.481} )

α =  cos⁻¹ (0.7715)

α = 39.51

α = 40°

β = cos⁻¹ ( \frac{a.j}{|a||j|} )

β = cos⁻¹ ( \frac{1}{\sqrt{42} } )

β = cos⁻¹ ( \frac{1}{6.481 } )

β = cos⁻¹ ( 0.1543 )

β = 81.12

β = 81°

γ = cos⁻¹ ( \frac{a.k}{|a|.|k|} )

γ = cos⁻¹ (\frac{4}{\sqrt{42} })

γ = cos⁻¹ (\frac{4}{6.481})

γ = cos⁻¹ (0.6172)

γ = 51.89

γ = 52°

<u>Conclusion:</u>

The direction cosines are:

\frac{5}{\sqrt{42} }, \frac{1}{\sqrt{42} }  and  \frac{4}{\sqrt{42} }  with respect to the x, y and z axes respectively.

The direction angles are:

40°,  81° and  52° with respect to the x, y and z axes respectively.

3 0
3 years ago
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