Find the 10th term of the following sequences T(2)=20 and the term-to-term rule is subtract 6
2 answers:
Answer:
-28.
Step-by-step explanation:
T(1) = 20 + 6 = 26.
This is an arithmetic series with:
nth term T(n) = 26 - 6(n - 1).
So T(10) = 26 - 6(10-1)
= 26 -54
= -28.
<h3>
Answer is -28</h3>
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Work Shown:
T(2) = 20 means the second term is 20
T(1) = 26 because we go backwards from what the rule says (subtract 6) to step back one term. Going forward, 26-6 = 20.
Since a = 26 is the first term and d = -6 is the common difference, the nth term is
T(n) = a + d*(n-1)
T(n) = 26 + (-6)(n-1)
T(n) = 26 - 6n + 6
T(n) = -6n + 32
Plugging n = 1 into the equation above leads to T(1) = 26. Using n = 2 leads to T(2) = 20.
Plug in n = 10 to find the tenth term
T(n) = -6n + 32
T(10) = -6(10) + 32
T(10) = -60+32
T(10) = -28
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