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sp2606 [1]
3 years ago
13

From a standard deck of cards a card will be chosen at random. What will be the probability the card is a 2

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0

Answer:

1/64 chance

Step-by-step explanation:

please leave me a brainliest


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Step-by-step explanation: BECAUSE IF A⇒B AND B⇒C

THEN  ¬A⇒C  I THINK ITS A THO

OR ¬A⇒¬C

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Find the average rate of change of the function f(x)=(x−2)2
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6 0
3 years ago
ESSENTIAL QUESTION CHECK-IN
EleoNora [17]

Answer:

parallelograms

Area = base * height

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8 0
3 years ago
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janice invests a total of 8000 in two different accounts. the first account returns 5%, while the second account returns 8%. if
Zinaida [17]

Answer:

"She invested $2500 in 5% account and $5500 in 8% account"

Step-by-step explanation:

Let the amount invested in 5% account be "x"

So, the amount invested in 8% account would be "8000 - x"

Interest amount is the percentage multiplied by amount invested. So

Interest of 5% account = 5% of x = 0.05x

Interest of 8% account = 8 % of 8000 - x = 0.08(8000 - x)

Total interest is the sum of these 2 expressions that EQUATES to 565 (given). Let's solve for x:

0.05x + 0.08(8000 - x) = 565\\0.05x+640-0.08x=565\\0.03x=75\\x=2500

and thus,

"8000 - x" = 8000 - 2500 = 5500

Hence,

She invested $2500 in 5% account and $5500 in 8% account

6 0
3 years ago
What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?
Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

AB = \sqrt{(11-4)^{2}+(3-3)^{2}}

AB = \sqrt{(7)^{2}+(0)^{2}}

AB = \sqrt{49}

\sqrt{49} =7

AB = 7 units

As take B(11, 3) to C (11, 9).

BC = \sqrt{(11-11)^{2}+(9-3)^{2}}

BC = \sqrt{(0)^{2}+(6)^{2}}

BC = \sqrt{36}

\sqrt{36} =6

BC = 6 units

As take C (11, 9) toD (4, 9).

CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}

CD = \sqrt{(7)^{2}+(0)^{2}}

CD = \sqrt{49}

\sqrt{49} =7

CD =  7 units

As take  D (4, 9) to  A (4, 3)

DA = \sqrt{(4-4)^{2}+(3-9)^{2}}

DA = \sqrt{(0)^{2}+(-6)^{2}}

DA = \sqrt{36}

\sqrt{36} =6

DA =  6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value  in the above

Area of rectangle =  7 × 6  

                             = 42 units ²

Therefore the area of a rectangle is 42 units ².

6 0
3 years ago
Read 2 more answers
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