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3 years ago

From a standard deck of cards a card will be chosen at random. What will be the probability the card is a 2

Mathematics

1 answer:

11Alexandr11 [23.1K]3 years ago

4 0

Answer:

1/64 chance

Step-by-step explanation:

please leave me a brainliest

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Solve for x. 3x−1=9x+2 Enter your answer in the box. x =

julia-pushkina [17]

Answer:

x= -1

Step-by-step explanation:

3x-1=2x2 (calculate the product)

3x-1=4x (move terms)

3 x - 4 x =1 (collect the terms)

- x = 1 (change the signs)

Solution is x = -1

3 0

3 years ago

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Trisha was making muffins from scratch. She scooped out 2 cups of all-purpose flour and estimated that it weighed 250 grams. Whe

Mice21 [21]

Answer:

first, she should have measured one cup of flower then estimated how much another one would weigh, and added the results together.

Step-by-step explanation:

hope it helps have a good day

3 0

2 years ago

Express (2-I) - (-1+3i) in the form of a + ib.

oksian1 [2.3K]

Answer:

$=3-4i$

Step-by-step explanation:

So we have:

$(2-i)-(-1+3i)$

First, distribute:

$=(2-i)+1-3i$

Combine like terms:

$=-i-3i+2+1$

Add:

$=-4i+3$

So, in the a+bi format, we will have:

$=3-4i$

7 0

2 years ago

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I hate copy and pastes

tangare [24]

Answer:

why they're so helpful

Step-by-step explanation:

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2 years ago

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Dwayne drove 18 miles to the airport to pick up his father and then returned home. On the return trip he was able to drive an av

Nesterboy [21]

Answer:

30 mph

Step-by-step explanation:

Let d = distance (in miles)

Let t = time (in hours)

Let v = average speed driving <u>to</u> the airport (in mph)

⇒ v + 15 = average speed driving <u>from</u> the airport (in mph)

Using: distance = speed x time

$\implies t=\dfrac{d}{v}$

Create two equations for the journey to and from the airport, given that the distance one way is 18 miles:

$\implies t=\dfrac{18}{v} \ \ \textsf{and} \ \ t=\dfrac{18}{v+15}$

We are told that the total driving time is 1 hour, so the sum of these expressions equals 1 hour:

$\implies \dfrac{18}{v} +\dfrac{18}{v+15}=1$

Now all we have to do is solve the equation for v:

$\implies \dfrac{18(v+15)}{v(v+15)} +\dfrac{18v}{v(v+15)}=1$

$\implies \dfrac{18(v+15)+18v}{v(v+15)}=1$

$\implies 18(v+15)+18v=v(v+15)$

$\implies 18v+270+18v=v^2+15v$

$\implies v^2-21v-270=0$

$\implies (v-30)(v+9)=0$

$\implies v=30, v=-9$

As v is positive, v = 30 only

So the average speed driving to the airport was 30 mph

(and the average speed driving from the airport was 45 mph)

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1 year ago

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