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Sholpan [36]
4 years ago
6

2−6(−5t+1)

Mathematics
2 answers:
VashaNatasha [74]4 years ago
6 0

Answer: I don't think any of those choices are correct.

Step-by-step explanation:

2-6*-5t+6

6*-5t+4

<h3>-30t+4</h3>
Ganezh [65]4 years ago
6 0

Answer:

2-6(5t+1) PEMDAS

Step-by-step explanation:

Parentheses (5t+1)

Subtraction 2-6

then take what you get for 2-6 and multiple it by whats inside of the parentheses. Then you will get your answer.    

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What is the approximate volume if this cone 9cm by 15cm
ArbitrLikvidat [17]
<em>Hello there, and thank you for asking your question here on brainly.

<u>Short answer: A. 1272 cm</u></em>³
<em>
Why?

When finding the volume of a cone, you use the formula <u>V = </u></em><u><em>πr²h/3. </em></u><em>R = 9, H = 15. V = π9²15/3 9</em>² = <em>81 | 15 / 3 = 5 | 3.14 * 81 = 254.34 | 254.34 * 5 = 1271.2 1272 rounded.

Hope this helped you! ♥</em>
5 0
3 years ago
Help help help please please
Vsevolod [243]
The answer is 10 miles
3 0
3 years ago
Trish is sorting bolts for her home repair business. She has an 8-pound bag of bolts. If each kitchen her team repairs requires
Lana71 [14]

Answer:

I mean it kind of speaks for itself

Step-by-step explanation:

8 divided by 1/5 is the same thing as 8 multiplied by 5

4 0
3 years ago
36z + 72 as a product of 2 factors
andreev551 [17]

Answer:

36(z + 2)

Step-by-step explanation:

First, find the GCF or greatest common factor. The GCF is the largest factor that all the numbers share. Both 72 and 36 are divisible by 36. 72 ÷ 36 = 2 and 36 ÷ 36 = 1. So, the factoring would look like 36(1z + 2) or 36 (z + 2)

4 0
2 years ago
What is the y-value of the vertex of the function f(x) = –(x + 8)(x – 14)? The y-value of the vertex is .
enot [183]
      Best Answer:  <span> y=18x^2+9x+14

y=18(x^2+(1/2)x + 1/16) + 14 - 9/8

y = 18(x + 1/4)^2 + 103/8


For y = a*(x - h)^2 + k, (h, k) the vertex

Your vertex: (- 1/4, 103/8)

Equation of axis of symmetry is x = (x-coordinate of vertex) OR x = - 1/4

y-intercept is y-value when x = 0, y = 14

x-intercept(s) do not exist for this upward opening parabola whose vertex y-value is above the x-axis.

The minimum of the function is the y-value of the vertex, 103/8.
=======================================...

Seems like Dizzle was in too much of a hurry and Jeff just copied Dizzle's answer.

The correct way of doing what dizzle TRIED to do:

For y = a*x^2 + b*x + c, the vertex occurs when x = - b / (2*a)

y=18x^2+9x+14

a = 18
b = 9

- b / (2*a) = - (9) / (2*18) = - 9 / 36 = - 1/4

Take that value for x, evaluate function at that value to get y.
=======================================...
Was so giddy about dizzle's faux pas that I originally did this work. May as well share it:

x-intercept(s) can be found by setting function equal to zero and solving:

y = 18(x + 1/4)^2 + 103/8

0 = 18(x + 1/4)^2 + 103/8

18(x + 1/4)^2 = - 103/8

(x + 1/4)^2 = - 103/144

x + 1/4 = +/- i*sqrt(103)/12

x = - 1/4 +/- i*sqrt(103)/12 OR x = [- 3 +/- i*sqrt(103)] / 12

These are the roots of the equation f(x) = 0

Since the roots are complex, there are no x-intercepts. The function is entirely above the x-axis. </span>
8 0
3 years ago
Read 2 more answers
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