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maxonik [38]
3 years ago
8

Find ef if e (1,-2) and f (7,6)

Mathematics
1 answer:
Elodia [21]3 years ago
7 0
Y-y1=a(x-x1)
a=(y2-y1)/(x2-x1)
a= (6-(-2))/(7-1)
a=8/6
a=4/3
y-6=4/3(x-7)
y-6=4/3x-28/3
y=4/3x-28/3+6
y=4/3x-10/3 >>ef
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