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grin007 [14]
2 years ago
13

Item 19 Question 1 A nurse is making identical first aid bags for patients using 72 antiseptic wipes, 55 adhesive bandages, and

36 packets of ointment. What is the greatest number of identical first aid bags the nurse can make with the least amount of items leftover? Describe the contents of each bag.
Mathematics
1 answer:
german2 years ago
5 0

Answer:

36 identical bags with 2 antiseptic wipes, 1 adhesive bandage and 1 ointment in each bag.

Leftovers: 19 adhesive bandages.

Step-by-step explanation:

First of all, let us try to find out the maximum number of identical first aid bags that can be prepared from the given contents.

The maximum number of bags that can be prepared will be equal to the quantity of the content which is available in minimum amount.

And that is number of packets of ointments.

Therefore, greatest number of bags that can be prepared is <em>36</em>.

Now, it can be seen that 72 antiseptic wipes are available.

72 is a multiple of 36.

Therefore, if we put 2 antiseptic wipes in each bag, no leftovers will be there for packet of ointments and antiseptic wipes.

Now, let us consider adhesive bandages.

Maximum of 1 adhesive bandages can be put in each bag because only 55 such bandages are available.

Therefore, the answer is:

<em>36 identical bags with 2 antiseptic wipes, 1 adhesive bandage and 1 ointment in each bag.</em>

<em>Leftovers: 19 adhesive bandages.</em>

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Answer: Choice D p(\text{x}) = 500(1.02)^{\text{x}}

Reason:

Exponential functions have the variable in the exponent.

Choice A is a polynomial, which means we can rule it out. Choice B is a log function, so we can rule it out also.

Choice C is a rational function because it is a ratio of two polynomials. This rules out choice C.

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2 years ago
A company that manufactures storage bins for grains made a drawing of a silo. The silo has a conical base, as shown below: The f
Romashka-Z-Leto [24]

The following that could be used to calculate the total volume of grains that can be stored in the silo is π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

To answer the question, we need to know what volume is.

<h3>What is volume?</h3>

This is the capacity of a material or container.

Since the silo is made of a cylindrical and a conical part, we need to find the volume of both parts.

<h3>Volume of cylindrical part.</h3>

So, the volume of the cylindrical part V = πr²h where

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So, V = πr²h

V = π(2 ft)²8 ft

<h3>Volume of the conical part</h3>

The volume of the conical part is given by V' = 1/3πr²h where

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Since the entire length of silo is 9.5 ft and length of cylindrical part is 8 ft, then the height of cone is h' = 9.5 ft - 8 ft

So, V' = 1/3πr²h'

V' = 1/3π(2 ft)²(9.5 ft - 8ft)

<h3>Total volume of grains in silo</h3>

The total volume of grains equals the total volume of the silo V" = V + V'

V" = π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

So, the following that could be used to calculate the total volume of grains that can be stored in the silo is π(2 ft)²8 ft + 1/3π(2 ft)²(9.5 ft - 8ft)

Learn more about volume here:

brainly.com/question/25248189

#SPJ1

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