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3 years ago

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Item 19 Question 1 A nurse is making identical first aid bags for patients using 72 antiseptic wipes, 55 adhesive bandages, and

36 packets of ointment. What is the greatest number of identical first aid bags the nurse can make with the least amount of items leftover? Describe the contents of each bag.

1 answer:

german3 years ago

5 0

Answer:

36 identical bags with 2 antiseptic wipes, 1 adhesive bandage and 1 ointment in each bag.

Leftovers: 19 adhesive bandages.

Step-by-step explanation:

First of all, let us try to find out the maximum number of identical first aid bags that can be prepared from the given contents.

The maximum number of bags that can be prepared will be equal to the quantity of the content which is available in minimum amount.

And that is number of packets of ointments.

Therefore, greatest number of bags that can be prepared is <em>36</em>.

Now, it can be seen that 72 antiseptic wipes are available.

72 is a multiple of 36.

Therefore, if we put 2 antiseptic wipes in each bag, no leftovers will be there for packet of ointments and antiseptic wipes.

Now, let us consider adhesive bandages.

Maximum of 1 adhesive bandages can be put in each bag because only 55 such bandages are available.

Therefore, the answer is:

<em>36 identical bags with 2 antiseptic wipes, 1 adhesive bandage and 1 ointment in each bag.</em>

<em>Leftovers: 19 adhesive bandages.</em>

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Answer:

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Question 3 A study was performed to determine whether men and women differ in their repeatability in assembling components on pr

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There is no sufficient evidence to support the claim that men and women differ in repeatability for this assembly task

Step-by-step explanation:

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$s_2 = 1.02$

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Determine if here is enough evidence

First, we need to state the hypotheses

$H_o: \sigma_1^2 = \sigma_2^2$

$H_1: \sigma_1^2 \ne \sigma_2^2$

Next, calculate the test statistic using:

$F = \frac{s_1^2}{s_2^2}$

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$F = 0.923$

Calculate the rejection region;

But first, calculate the degrees of freedom

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$df_1 =25 - 1$

$df_1 =24$

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$df_2 = 21 - 1$

$df_2 = 20$

Using the F Distribution: table

$c = \frac{\alpha}{2}$

$c = \frac{0.02}{2}$

$c = 0.01$

At 0.01 level (check row 20 and column 24), the critical value is:

<em></em> $f_{0.01,24,20} = 2.86$ <em> --- the upper bound</em>

At 0.01 level (check row 24 and column 20), the critical value is:

$f_{0.01,20,24} = 2.74$

Calculate the inverse F distribution.

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If the test statistic falls within this region, then the null hypothesis is rejected

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$0.365 < 0.923 < 2.86$

<em>The above inequality is true; so, the null hypothesis is rejected.</em>

<em>This implies that, there is no sufficient evidence.</em>

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