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Tresset [83]
3 years ago
14

Rewrite the equation by completing the square. 4 x^{2} +8 x +3 = 0solve equation in (x+__)^2=__

Mathematics
1 answer:
sergiy2304 [10]3 years ago
8 0

Answer:

4(x+1)^2-1

Step-by-step explanation:

use b/2^2 in order to create a new term to completed the square

hope this helps ''whole lotta love'' NUNU

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The triangles are similar. Find the value of x.
LUCKY_DIMON [66]

Answer: 95

Step-by-step explanation:

I am in geometry this year. We know by the AA thorem that all three angles are similar. Since both triangles have sides 45 and 40. We know that the last side has to 95.

Hope this helps :)

5 0
3 years ago
Read 2 more answers
Solve -2a-5&gt;3. which graph shows the solutions?<br>​
Flura [38]

Answer:

see explanation

Step-by-step explanation:

Given

- 2a - 5 > 3 ( add 5 to both sides )

- 2a > 8

Divide both sides by - 2, reversing the direction of the inequality sign as a consequence of dividing by a negative quantity

a < - 4

Since a is less than we require an open circle at - 4 on the number line.

Since less than the arrow head is pointing to the left, that is

Graph A, the top graph illustrates the solution

8 0
3 years ago
Which function is equivalent to h(x) = 10x?+ 9x - 1?
Elis [28]

Answer:

i think it's this Bh(x) = (x + 1)(10x - 1)

4 0
3 years ago
Find the probability of getting four consecutive aces when four cards are drawn without replacement from a standard deck of 52 p
posledela

Answer:

<em>P=0.0000037</em>

<em>P=0.00037%</em>

Step-by-step explanation:

<u>Probability</u>

A standard deck of 52 playing cards has 4 aces.

The probability of getting one of those aces is

\displaystyle \frac{4}{52}=\frac{1}{13}

Now we got an ace, there are 3 more aces out of 51 cards.

The probability of getting one of those aces is

\displaystyle \frac{3}{51}=\frac{1}{17}

Now we have 2 aces out of 50 cards.

The probability of getting one of those aces is

\displaystyle \frac{2}{50}=\frac{1}{25}

Finally, the probability of getting the remaining ace out of the 49 cards is:

\displaystyle \frac{1}{49}

The probability of getting the four consecutive aces is the product of the above-calculated probabilities:

\displaystyle P= \frac{1}{13}\cdot\frac{1}{17}\cdot\frac{1}{27}\cdot\frac{1}{49}

\displaystyle P= \frac{1}{270,725}

P=0.0000037

P=0.00037%

3 0
3 years ago
Write an equivalent expression for (x - 11)(x + 9).
vodka [1.7K]

Answer:

x²-2x-99

Step-by-step explanation:

(x-11)(x+9) - foil method

x times x = x squared

x times 9 = 9x

-11 times x = -11x

-11 times 9 = -99

x squared + 9x + 11x + -99

x squared-2x-99

7 0
3 years ago
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