1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alex787 [66]
3 years ago
8

In a jewelry store, rings makeup 5/9 of the inventory. Earrings make up 4/15 of the inventory. How many times greater is the rin

g inventory than the earring inventory?
Mathematics
1 answer:
Free_Kalibri [48]3 years ago
4 0
First let's make the denominators equal, so that we can compare the two fractions more easily.
To do this, we have to find a number that both 15 and 9 divide into. The smallest number that this can happen to is 45.

15 x 3 = 45
9 x 5 = 45

So we have to multiply 15 by 3 in order to make it into 45. If we're changing the denominator, the numerator must change too, by the same multiplier.

4 ---> 4 x 3 = 12
--
15 ---> 15 x 3 = 45

4/15 = 12/45


5 ---> 5 x 5 = 25
--
9 ---> 9 x 5 = 45

5/9 = 25/45

To find how many times more rings there are, we divide 25 by 12. As the result of this isn't an integer, we leave the answer as a fraction:

There rings inventory is 25/12 times bigger than the earrings inventory.
You might be interested in
The outside temperature at midnight us -7° C . By 11 am the temperature has risen by 12°C what is the temperature at 11 am
Yanka [14]

Answer:

5°C

Step-by-step explanation:

We need to add 12 onto the -7:

-7 + 12 = 5

3 0
3 years ago
Please help me answer all parts of the question in the photo.
goldenfox [79]
z_1=4+2i\\z_2=-1+2i\\\overline(z_2)=\sqrt{(-1)^2+(2i)^2}=\sqrt{1-4}=i\sqrt{3}\\ z_1+\overline(z_1)=4+2i+\sqrt{4^2+(2i)^2}=4+2i+\sqrt{16-4}=4+\sqrt{12}+2i\\z_2+\overline(z_2)=-1+2i+\sqrt{(-1)^2+(2i)^2}=-1+2i+\sqrt{1-4}=-1+(2+\sqrt{3})i
3 0
3 years ago
What is the answer for (14÷49)+((18+7)×9).
balu736 [363]
228.5 I believe. 14/49 is 3.5. 18+7 is 25x9 is 225. 225+3.5 would be 228.5
3 0
3 years ago
You hike 190 meters up a steep hill that has a 33∘ angle of elevation as shown in the diagram.
erik [133]

Answer:

b = 159 m

a = 103 m

angle B is 57 degrees

Step-by-step explanation:

Let’s start with getting the measure of angle B

Mathematically, since we have a right triangle , we have to subtract the given angle from 90 to get the other acute angle

So we have the measure of B as;

90-33 = 57 degrees

To get the value of a, we use the appropriate trigonometric ratio

a faces the angle 33, that makes it an opposite to that angle

190 faces the right angle and that makes it the hypotenuse

Mathematically , the relationship between the two is that trigonometrically, they are related by the sine which is the ratio of the opposite to the hypotenuse

so, we have it that;

sine 33 = a/190

a = 190 * sine 33

a = 103 m

to get b, it is adjacent to the given angle

So with the hypotenuse, the ratio between it and the hypotenuse is the cosine

so;

cos 33 = b/190

b = 190 * cos 33

b = 159 m

4 0
3 years ago
Solve for y: 7x+8y s 14-16
romanna [79]

Answer:

y≤ -1/4 - 7x/8

Step-by-step explanation:

7 0
3 years ago
Other questions:
  • What is .133 repeating as a fraction?
    6·2 answers
  • What is the slope of the line shown? (Hint: Use given points)
    14·2 answers
  • A Ferris wheel has a diameter of 110 meters. If the Ferris wheel makes one full revolution every every 20 minutes, how far does
    7·2 answers
  • Given cos x =12/13 And sin x = 5/13<br> what is ratio for tan x
    9·2 answers
  • Which part of the ear carries sound messages to the brain?
    6·1 answer
  • Find the value of x for this trapezoid.
    13·1 answer
  • Please help fasttttttt
    9·1 answer
  • Show Your work to find X
    11·1 answer
  • 1. Prove that<br><br> 2 tan x / 2- sec^2 x = tan 2x.
    7·1 answer
  • Squaring a number is multiplying it by itself. Finding a square root is dividing and trying to find the two numbers that will mu
    5·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!