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3 years ago

Five oranges cost $2.Find the cost of two dozen oranges.

2 answers:

5 0

If 5 oranges cost $2 you can divide 2 by 5 to get the cost of each individual orange and then you must multiply that by 24 to get the total cost.

kaheart [24]3 years ago

4 0

So if 5 oranges cost 2 dollars, then 10 cost 4, 15 cost 6, 20 cost 8,
and 25 cost 10. We need 24, so now we need to find out the cost for 24 oranges.
Looking at how much they go up by, we can see that each time it goes up by about 0.5
So your final answer would be: 2 dozen oranges cost $9.50

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MATH HELP ASAP!! 10) Which square root is a whole number?

Stella [2.4K]

Answer:

C - 256

Step-by-step explanation:

256 / 16 = 16.

8 0

3 years ago

Read 2 more answers

The sides of the cubes are numbered 1 through 6. if they are both tossed, what is the probability that they will both be a 3?

Elodia [21]

Answer: Option 'C' is correct.

Step-by-step explanation:

Since we have given that

the sides of the cubes are numbered 1 through 6,

So,

$P(\text{ getting a 3})=\frac{1}{6}$

if they are both tossed ,

Probability (getting that they will both be a 3) is given by

$=\frac{1}{6}\times \frac{1}{6}\\\\=\frac{1}{36}$

(∵ $\\P(\text{A and B})=P(A\cap B)=P(A).P(B)\\$ )

Therefore, Option 'C' is correct.

4 0

2 years ago

Read 2 more answers

David and Lacey are 2000 feet apart on a coastline. They each look at the same boat in the water. The angle between the coastlin

Ulleksa [173]

By using the given distances and directions, we have;

Part A: 1083.5 feet

Part B: 1921.37 feet

Part C: 58.05°

<h3>How can the distances and directions be calculated?</h3>

The distance between David and Lacey = 2000 feet

David's angle to the boat = 70°

Lacey's angle to the boat = 32°

Part A

The distance of the boat from David is found as follows;

Imaginary lines drawn from the boat to David and then to Lacey form a triangle.

In the triangle, let A = 70°

B = 32°

Therefore by the sum of angles in a triangle, we have;

C = 180° - (70° + 32°) = 78°

By using sine rule we have;

$\frac{a}{sin(A)} = \frac{b}{sin( B )} = \frac{c}{sin(C)}$

David's distance from the boat, b, is therefore;

$\frac{b}{sin( 32 )} = \frac{2000}{sin(78)}$

The angle subtended by the coastline, C, is therefore;

$b = \frac{2000}{sin(78)} \times sin( 32 ) = 1083.5$

David's distance from the boat is 1083.5 feet

Part B

The distance between the boat and Lacey is found as follows;

$\mathbf{ \frac{a}{sin( 70)} }= \frac{2000}{sin(78)}$

$a = \frac{2000}{sin(78)} \times sin( 70 ) = 1921.37$

Lacey's distance from the boat is 1921.37 feet

Part C

When b = 1200 feet, we have;

Finding the vertical distance of the boat from the coastline, we have;

1083.5 × sin(70) = 1018.17

We have;

$\frac{1200}{sin(90)} = \frac{1018.17}{sin( B' )}$

${sin( B' )} = \frac{sin(90)}{1200} \times 1018.17$

The angle between the coastline and his view to the boat, B', is therefore;

B' = arcsine (1018.17÷1200) = 58.05°

Learn more about sine rule here:

brainly.com/question/4372174

#SPJ1

4 0

1 year ago

How do you solve this? please help me guys!

azamat

3y -2 > 5
3y -2 +2 > 5+2
3y > 7
y > 7/3

6 0

3 years ago

Read 2 more answers

Write an equation of a line that includes the point (22,12) and has a slope of 4 in standard form

Marina CMI [18]

Because you're given a point and the slope, you're going to use point-slope form.

Point slope form: y-y1=m(x-x1)

You have to put your given values into the equation.

y-12=4(x-22)

Because it wants the equation in standard form, you leave the equation as is.

I hope I was able to help. Best of luck!

6 0

3 years ago