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zlopas [31]
3 years ago
11

PLEASE ANSWER How many liters of a 35% salt solution must be mixed with 20 liters of 70% salt solution to obtain a solution that

is 45% salt?
Mathematics
1 answer:
laila [671]3 years ago
8 0

Answer:

50 liters

Step-by-step explanation:

Amount of salt in the 35% solution + amount of salt in the 70% solution = amount of salt in the 45% solution

0.35 x + 0.70 (20) = 0.45 (x + 20)

0.35 x + 14 = 0.45 x + 9

5 = 0.1 x

x = 50

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A boat travels 36 miles in 1.5 hours ans then in 14 miles in 0.75 hour. what is the average speed?
allochka39001 [22]

The average speed can be obtained by the formula:

V_{\text{average}}=\dfrac{\text{total distance}}{\text{total time}}.

If a boat travels 36 miles in 1.5 hours ans then in 14 miles in 0.75 hour, then find:

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A cooler contains fifteen bottles of sports drink: eight lemon-lime flavored and seven orange flavored
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Answer:

Mutually exclusive,

P(\text{Lemon-lime or orange})=\frac{2}{3}

Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the  probability.

A cooler contains twelve bottles of sports  drink: four lemon-lime flavored, four  orange flavored, and four fruit-punch  flavored. You randomly grab a bottle. It  is a lemon-lime or an orange.

Let us find probability of finding one lemon lime drink.

P(\text{Lemon-lime})=\frac{\text{Number of lemon lime drinks}}{\text{Total drinks}}

P(\text{Lemon-lime})=\frac{4}{12}

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P(\text{Orange})=\frac{\text{Number of orange drinks}}{\text{Total drinks}}

P(\text{Orange})=\frac{4}{12}

P(\text{Orange})=\frac{1}{3}

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})

P(\text{Lemon-lime or orange})=\frac{1}{3}+\frac{1}{3}

P(\text{Lemon-lime or orange})=\frac{1+1}{3}

P(\text{Lemon-lime or orange})=\frac{2}{3}

Therefore, the probability of choosing a lemon lime or orange is \frac{2}{3}.

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