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3 years ago

Multiply.

Mathematics

2 answers:

Mariana [72]3 years ago

8 0

Answer:

$\frac{9}{5}$

Step-by-step explanation:

3 * 3/5

~Make the 3 improper fraction (note that you can make any whole number a fraction if you put a 1 as the denominator)

3/1 * 3/5

~Multiply both numerators and denominators

9/5

Best of Luck!

kondaur [170]3 years ago

4 0

Answer:

9/5 or 1 $\frac{4}{5}$

Step-by-step explanation:

when multiplying a whole number and a fraction, a fun trick i learned is multiply by the top and divide by the bottom.

3·3=9

9÷5= $\frac{9}{5}$

as an improper fraction it would be

1 $\frac{4}{5}$

Plz mark as brainliest and rate if i was correct.

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Suppose that an airline quotes a flight time of 128 minutes between two cities. Furthermore, suppose that historical flight reco

ANTONII [103]

Answer:

(a) The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

(b) The value of P (129 ≤ X ≤ 146) is 0.3462.

(c) The probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

Step-by-step explanation:

The random variable X is defined as the flight time between the two cities.

Since the random variable X denotes time interval, the random variable X is continuous.

(a)

The random variable X is Uniformly distributed with parameters a = 10 minutes and b = 154 minutes.

The probability density function of X is:

$f_{X}(x)=\frac{1}{b-a};\ a$

(b)

Compute the value of P (129 ≤ X ≤ 146) as follows:

Apply continuity correction:

P (129 ≤ X ≤ 146) = P (129 - 0.50 < X < 146 + 0.50)

= P (128.50 < X < 146.50)

$=\int\limits^{146.50}_{128.50} {\frac{1}{154-102}} \, dx$

$=\frac{1}{52}\times \int\limits^{146.50}_{128.50} {1} \, dx$

$=\frac{1}{52}\times (146.50-128.50)$

$=0.3462$

Thus, the value of P (129 ≤ X ≤ 146) is 0.3462.

(c)

It is provided that a randomly selected flight between the two cities will be at least 3 minutes late, i.e. X ≥ 128 + 3 = 131.

Compute the value of P (X ≥ 131) as follows:

Apply continuity correction:

P (X ≥ 131) = P (X > 131 + 0.50)

= P (X > 131.50)

$=\int\limits^{154}_{131.50} {\frac{1}{154-102}} \, dx$

$=\frac{1}{52}\times \int\limits^{154}_{131.50} {1} \, dx$

$=\frac{1}{52}\times (154-131.50)$

$=0.4327$

Thus, the probability that a randomly selected flight between the two cities will be at least 3 minutes late is 0.4327.

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bixtya [17]

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Question 4

Elanso [62]

Answer:

a $A = 30 + 0.45 n$

b $A = 90.3$

c 0 customers

Step-by-step explanation:

Given

$Base\ Amount = 30$

$Rate = 0.45$ per customer

Solving (a): Amount (A) on n customers

This is calculated as:

$A = Base\ Amount + Rate * n$

$A = 30 + 0.45 * n$

$A = 30 + 0.45 n$

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In this case: n = 134

So:

$A = 30 + 0.45 * 134$

$A = 30 + 60.3$

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At noon, the amount is 30.

So:

$A = 30 + 0.45 n$

$30 = 30 + 0.45n$

Collect like terms

$0.45n = 30 - 30$

$0.45n =0$

$n = 0$

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lara31 [8.8K]

Answer:

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Step-by-step explanation:

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