Question

Use the information to answer the questions.

Answer 1

Answer:

Part 1) The length of two sides and the measure of the included angle (Side-Angle-Side)

Part 2) $b^2=a^2+c^2-2(a)(c)cos(B)$  

Part 3) $b=11.6\ in$

Step-by-step explanation:

we have

In the triangle ABC

$a=11\ in\\c=9\ in\\B=70^o$

Part 1) Which information about the triangle is given?

In this problem we have the length of two sides and the measure of the included angle (Side-Angle-Side)

see the attached figure to better understand the problem

Part 2) Which formula can you use ti find b?

I can use the law of cosines

$b^2=a^2+c^2-2(a)(c)cos(B)$  

we have

$a=11\ in\\c=9\ in\\B=70^o$

substitute the given values

$b^2=11^2+9^2-2(11)(9)cos(70^o)$

$b^2=202-67.72$  

$b=11.59\ in$

Part 3) What is b, rounded to the nearest tenth?

Remember that

To Round a number

a) Decide which is the last digit to keep  

b) Leave it the same if the next digit is less than $5$ (this is called rounding down)  

c) But increase it by  $1$ if the next digit is  $5$ or more (this is called rounding up)

In this problem we have

$11.59\ in$

We want to keep the digit $5$

The next digit is $9$ which is 5 or more, so increase the "5" by 1 to "6"

therefore

$b=11.6\ in$