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PSYCHO15rus [73]
3 years ago
6

Use the information to answer the questions.

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

Part 1) The length of two sides and the measure of the included angle (Side-Angle-Side)

Part 2) b^2=a^2+c^2-2(a)(c)cos(B)  

Part 3) b=11.6\ in

Step-by-step explanation:

we have

In the triangle ABC

a=11\ in\\c=9\ in\\B=70^o

Part 1) Which information about the triangle is given?

In this problem we have the length of two sides and the measure of the included angle (Side-Angle-Side)

see the attached figure to better understand the problem

Part 2) Which formula can you use ti find b?

I can use the law of cosines

b^2=a^2+c^2-2(a)(c)cos(B)  

we have

a=11\ in\\c=9\ in\\B=70^o

substitute the given values

b^2=11^2+9^2-2(11)(9)cos(70^o)

b^2=202-67.72  

b=11.59\ in

Part 3) What is b, rounded to the nearest tenth?

Remember that

To Round a number

a) Decide which is the last digit to keep  

b) Leave it the same if the next digit is less than 5 (this is called rounding down)  

c) But increase it by  1 if the next digit is  5 or more (this is called rounding up)

In this problem we have

11.59\ in

We want to keep the digit 5

The next digit is 9 which is 5 or more, so increase the "5" by 1 to "6"

therefore

b=11.6\ in

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Please see the image and help with this homework problem. thank you!
dimulka [17.4K]

we have the function

E=\sin \frac{\pi}{14}t

Part a

For t=7

substitute in the given function

\begin{gathered} E=\sin \frac{\pi}{14}7 \\ E=1 \end{gathered}

For t=14

\begin{gathered} E=\sin \frac{\pi}{14}14 \\ E=0 \end{gathered}

For t=21

\begin{gathered} E=\sin \frac{\pi}{14}21 \\ E=-1 \end{gathered}

For t=28

\begin{gathered} E=\sin \frac{\pi}{14}28 \\ E=0 \end{gathered}

For t=35

\begin{gathered} E=\sin \frac{\pi}{14}35 \\ E=1 \end{gathered}

Observation: The values of E varies from -1 to 1, including the zero

Part B

Remember that

The Period goes from one peak to the next

so

Period=2pi/B

B=pi/14

Period=(2pi)/(pi/14)=2pi*14/pi=28

<h2>the period is 28 days</h2>
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