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Anestetic [448]
3 years ago
7

Solve for x: −3|x − 3| = −6

Mathematics
1 answer:
lozanna [386]3 years ago
7 0
-3|x-3|=-6
divide both sides by -3
|x-3|=2
assume
x-3=2 and
x-3=-2

x-3=2
add 3
x=5

x-3=-2
add 3
x=1

x=5 or 1
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Two integers, a and b have product of -48 what is the greatest possible sum of a and b.
dusya [7]
The factors of 48 are:
1 x 48
2 x 24
3 x 16
4 x 12
6 x 8
and visa versa:   48 x 1  etc.

To make the product negative, one of the factors has to be positive and one has to be negative.  To find the greatest sum, make the bigger number the positive factor and the smaller number the negative factor.  So, -1 x 48 = -48 and the sum of -1 + 48 = 47 which would be the greatest possible sum.
6 0
3 years ago
Slove by using elimination <br> 3x+7y=27 <br> -3x+y=21
tankabanditka [31]

Answer:

x = -5

y = 6

Step-by-step explanation:

3x + 7y = 27      --------------(I)

-3x + y = 21        -----------(II)

Add equation (I) & (II) and so x will be eliminated and we can find the value of y.

(I)      3x + 7y = 27    

(II)    <u> -3x + y = 21  </u>      {add}

                8y = 48

                   y = 48/8

                   y = 6

Plugin y = 6 in equation (I)

3x +7*6 = 27

3x + 42 = 27

       3x = 27 - 42

       3x = -15

         x = -15/3

x = -5

8 0
3 years ago
X²+y²-6x+14y-1=0<br> and please show your work so I can learn
Eva8 [605]

Hello there,

I hope you and your family are staying safe and healthy during this winter season.

x^2 + y^2 -6x+14y-1=0

We need to use the Quadratic Formula*

x =\frac{-b+\sqrt{b^2}-4ac }{2a} , \frac{-b-\sqrt{b^2} -4ac }{2a}

Thus, given the problem:

a = 1, b=-6, c=y^2+14y-1

So now we just need to plug them in the Quadratic Formula*

x=\frac{6+2\sqrt{(-6)^2-4(y^2+14y-1)} }{2} , x=\frac{6-\sqrt{(-6)^2-4(y^2+14y-1)} }{2}

As you can see, it is a mess right now. Therefore, we need to simplify it

x=\frac{6+2\sqrt{10-y^2-14y} }{2}, x = \frac{6-2\sqrt{10-y^2-14y} }{2}

Now that's get us to the final solution:

x=3+\sqrt{10-y^2-14y}, x=3-\sqrt{10-y^2-14y}

It is my pleasure to help students like you! If you have additional questions, please let me know.

Take care!

~Garebear

3 0
2 years ago
Determine the unknown angle measures in the figure.<br><br>HELP NOW!!! please
maw [93]

Answer:

m∠1=80°

m∠2=112°

m∠3=131°

m∠4=80°

m∠5=37°

Step-by-step explanation:

First you have to find m∠2

To do that find m∠6 (I created this angle shown in pic below)

Find m∠6 by using the sum of all ∠'s in a Δ theorem

m∠6=180°-(63°+49°)

m∠6=68°

Now you can find m∠2 with the supplementary ∠'s theorem

m∠2=180°-68°

m∠2=112°

Then you find m∠5 using the sum of all ∠'s in a Δ theorem

m∠5=180°-(112°+31°)

m∠5=37°

Now you can find m∠1

m∠1=180°-(63°+37°)

m∠1=180°-100°=80°

m∠4 can easily be found too now:

m∠4=180°-(63°+37°)

m∠4=80°

m∠3=180°-49°

m∠3=131°

8 0
3 years ago
a farmer plowed 35 acres which yielded 5691 bushels of corn. if he plants the same type of corn in 42 acres, how many bushels sh
DENIUS [597]

Answer:

6829 bushels should be expect go harvest

7 0
3 years ago
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