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slavikrds [6]
3 years ago
15

If 15/3 greater than 7, then 15/7 is less than 3 true or false

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0

Answer:

True

Step-by-step explanation:

15/7 is about 2.14 which is less than 3

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Brian buys candy that costs 4 per pound. He will buy at least 8 pounds of candy. What are the possible amounts he will spend on
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32 pound but I dunno what that is in american dollars

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-43 – 9x = -7 – 3(5x + 6)<br> Answer?
lilavasa [31]

Answer:

Simplifying

9x + 7 = 5x + -3

Reorder the terms:

7 + 9x = 5x + -3

Reorder the terms:

7 + 9x = -3 + 5x

Solving

7 + 9x = -3 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

7 + 9x + -5x = -3 + 5x + -5x

Combine like terms: 9x + -5x = 4x

7 + 4x = -3 + 5x + -5x

Combine like terms: 5x + -5x = 0

7 + 4x = -3 + 0

7 + 4x = -3

Add '-7' to each side of the equation.

7 + -7 + 4x = -3 + -7

Combine like terms: 7 + -7 = 0

0 + 4x = -3 + -7

4x = -3 + -7

Combine like terms: -3 + -7 = -10

4x = -10

Divide each side by '4'.

x = -2.5

Simplifying

x = -2.5

make me brainiest plz!!!

Step-by-step explanation:

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I need to use the Pythagorean Theorem to find X. I don’t know how to do that!!
frutty [35]

Answer:

17) x=8

18) x=\sqrt{189} or x= 3\sqrt{21}

Step-by-step explanation:

So the rule is a^{2} +b^{2} =c^{2}, "c" being the hypothenuse, or the long line that is opposite to the right angle.

17) We know that both values of x are equal to each other, which makes everything 10x easier!

                                               x^{2} +x^{2} =(8\sqrt{2})  ^{2}

(by the way we know the x values are our a and b values because they are legs! the way I like to remember the legs is that they are connected to the right angle box, and therefore support the hypothenuse)

<em>simplify</em> (╥︣﹏╥)    

                                                2x^2=8^2(\sqrt{2} )^{2}  

                                                  2x^2=64(2)

                                                   2x^2=128    

                                                  x^{2}= 128/2  

                                                     x^{2} =64

                                                        x=8      

18) Just pretend that the flipped triangle doesn't exist. It's parallel to the other triangle with values on it, and basically servers no purpose other than being parallel to the sister triangle :)

Anyways, since we know the hypothenuse (15) but we don't know one of our leg values (x), we're going to change our equation a bit!

                                                    c^{2} - b^{2} = a^{2}

It doesn't matter if you put the one leg value in a or b, just as long as you stick to that same equation you started with the entire time!

                                                   15^{2} -6^{2} =x^{2}

                                                   225-36=x^{2}  

                                                     x^{2} =189

                                               x=\sqrt{189}=3\sqrt{21}

        The more you do these, the easier they'll get, so don't worry!

                           

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