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vodomira [7]
3 years ago
15

I need some help I will give you brainiest.

Mathematics
1 answer:
marusya05 [52]3 years ago
8 0
2 grams because 1000 milligrams = 1 gram
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I don’t know what I’m doing wrong. I need help understanding this problem please...
denpristay [2]

Answer:

Step-by-step explanation:

Cost (C) depends on the number of miles traveled (x).

So C is the dependent variable.

Or C(x) if they want you to be more specific.

x is your independent variable.

Miles driven do not depend on anything.

5 0
3 years ago
The temperature in Carla’s city is decreasing. For the past 9 days, the temperature has decreased by 3 degrees Fahrenheit each d
Sav [38]

Answer:

9/3

Step-by-step explanation:

7 0
3 years ago
2x-y=-1 in slope intercept form
AnnyKZ [126]

Answer:

y=-2x+1

Step-by-step explanation:

y=Mx+b is the slope formula. You want to move y over to the other side to get the equation equal to y

4 0
3 years ago
Tyna simplified the expression StartFraction 3 x cubed Over 12 x Superscript negative 2 Baseline EndFraction to StartFraction x
Yuki888 [10]

Answer:

She divided the coefficients incorrectly

Step-by-step explanation:

A. She divided the coefficients incorrectly.

B. She added the exponents instead of subtracting them.

C. She divided the coefficients instead of subtracting them.

D. She subtracted the exponents instead of dividing them.

Correct calculation:

3x³/12x^-2

= 3x³ ÷ 12x^-2

= 3x³ ÷ 1/12x²

= 3x³ × 12x²/1

= 36x^5

Tyna's calculation:

3x³/12x^-2 = x/4

3 0
3 years ago
(1CQ) Determine whether the series -8/5+32/25-128/125+... is convergent or divergent.
Ivan

Answer:

The series is convergent answer ⇒ (a)

Step-by-step explanation:

* The series is -8/5 + 32/25 + -128/125 + ........

- It is a geometric series with:

- first term a = -8/5 and common ratio r = 32/25 ÷ -8/5 = -4/5

* The difference between the convergent and divergent

  in the geometric series is :

- If the geometric series is given by  sum  = a + a r + a r² + a r³ + ...

* Where a is the first term and r is the common ratio

* If |r| < 1 then the following geometric series converges to a / (1 - r).  

- Where a/1 - r is the sum to infinity

* The proof is:

∵ S = a(1 - r^n)/(1 - r) ⇒ when IrI < 1 and n very large number

∴ r^n approach to zero

∴ S = a(1 - 0)/(1 - r) = a/(1 - r)

∴ S∞ = a/1 - r

* If |r| ≥ 1 then the above geometric series diverges

∵ r = -4/5

∴ IrI = 4/5

∴ IrI < 1

∴ The series is convergent

3 0
4 years ago
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