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IgorC [24]
3 years ago
12

In the diagram, the length of segment TR can be represented by 5x – 4. Line n is a perpendicular bisector of line segment T V. I

t intersects line segment T V at point R. Line n also contains points Q and S. Line segment Q V is 3 x + 4. Line segment R V is 2 x + 5. Line segment T S is 6 x minus 3. What is the length of segment VS? 3 units 11 units 13 units 15 units

Mathematics
2 answers:
lakkis [162]3 years ago
5 0

Answer:

15

Step-by-step explanation:

The answer is 15 because you have to solve the equation which gets you 15

first cancel out the x

Then you will get ur answer

HOPE THIS HELP:)

STAY SAFE

Aneli [31]3 years ago
4 0

Answer:

it is 15. just did the test. (edg. 2020)

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The intercepts of the third degree polynomial corresponds to the zeros of the equation
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We graph the equation in the attached file.

7 0
3 years ago
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-4 - (-9). please help
IgorLugansk [536]

Answer:

\boxed{  \bold{ \huge{ \boxed{ \sf{5}}}}}

Step-by-step explanation:

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lara31 [8.8K]

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Step-by-step explanation:

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castortr0y [4]
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7 0
3 years ago
In the figure given below CP=x+3, PA=3x+19, CQ=x and QB=3x+4 then, what value of x will make PQ || AB?
zhenek [66]

Given that

PQ || AB

CP = x+3

PA = 3x+19

DC = x+3

CA = x

QB = 3x+4

We know that

By Basic Proportionality Theorem,

CP / PA = CQ / QB

On substituting these values in the above formula

⇛ (3x+19) / (x+3) = (3x+4) / x

On applying cross multiplication then

⇛ x(3x+19) = (3x+4)(x+3)

⇛ 3x²+19x = 3x(x+3)+4(x+3)

⇛ 3x²+19x = 3x²+9x+4x+12

⇛ 3x²+19x = 3x²+13x+12

⇛ 3x²+19x-3x²-13x = 12

⇛ (3x²-3x²)+(19x-13x) = 12

⇛ 0+6x = 12

⇛ 6x = 12

⇛ x = 12/6

⇛ x = 2

∴ , x = 2

<u>Answer:</u> The value of x for the given problem is 2

<em>Additional</em><em> comment</em><em>:</em>

<u>Basic Proportionality Theorem</u>

" A line drawn parallel to the one side of a triangle intersecting other two sides at two different points, then the line divides the other two sides in the same ratio".

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