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AlladinOne [14]
3 years ago
5

Ronique recorded the number of games that the school softball team won each year for the past 7 years: 31, 24, 32, 22, 34, 28, 3

8. Ronique's team won at least
games in 75% of the seasons that they played.
Mathematics
2 answers:
makvit [3.9K]3 years ago
4 0

Answer:

156

Step-by-step explanation:

Mashcka [7]3 years ago
3 0

Answer:

156

Step-by-step explanation:

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What is –22x+9x simplified ​
rodikova [14]

Answer:

I think -13 x and thanks for point

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3 years ago
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Find the height of a square pyramid that has a volume of 12 cubic feet and a base length of 3 feet. 1.5 feet 2 feet 3 feet 4 fee
zaharov [31]
So the pyramid looks like the one in the picture below.

notice, the bottom of the pyramid is a square, thus is called that, and each side is 3 units long, thus

\bf \textit{volume of a pyramid}\\\\
V=\cfrac{1}{3}Bh~~
\begin{cases}
B=area~of\\
\qquad its~base\\
h=height\\
----------\\
V=12\\
B=\stackrel{3\times 3}{9}
\end{cases}\implies 12=\cfrac{(9)h}{3}\implies 12=3h
\\\\\\
\cfrac{12}{3}=h\implies 4=h

6 0
3 years ago
What is pr and sr please
Sonbull [250]

Answer:

Answer C = PR =8   SR =6

Step-by-step explanation:

PR = x-1

PR = 9-1 = 8

PR x = 8

SR = x-3

SR = 9-3 = 6

SR x = 6

3 0
3 years ago
What is the solution to the equation?
mart [117]
C is the correct answer .. hopes this helps :)
8 0
3 years ago
An investment analyst takes a random sample of 100 aggressive equity funds and calculates the average beta as 1.7. The sample be
I am Lyosha [343]

Answer:

B) 1.622 to 1.778 includes the mean of the population beta.

Step-by-step explanation:

We have the standard deviation for the sample, so the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 100 - 1 = 99

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 99 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 1.9842

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.9842\frac{0.4}{\sqrt{100}} = 0.078

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.7 - 0.078 = 1.622.

The upper end of the interval is the sample mean added to M. So it is 1.7 + 0.078 = 1.778.

Thus the correct answer is given by option B.

8 0
3 years ago
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