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3 years ago

Fran has a poster that measures 3/4 square yard in area. The length of the poster is 1/3 yard. What is the width of the poster.i

Mathematics

1 answer:

Brums [2.3K]3 years ago

3 0

Answer:

2 1/4 yards.

Step-by-step explanation:

Width = area / length

Width = 3/4 / 1/3

= 3/4 * 3

= 9/4

= 2 1/4 yards.

The width is actually the length!! but nvm.

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Estimate the unit rate if 12 pairs of socks sell for $5.79.

11111nata11111 [884]

If 12 pairs of socks sell for $5.79, then the unit rate is 12 : 5.79. If we want to find a unit rate for one pair of socks, we need to divide 5.79 by 12:
5.79 / 12 = 0,4825
So the unit rate is 1 : 0.4825
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3 0

3 years ago

Point 6,8 lies in which quadrant

OverLord2011 [107]

Answer:

Quadrant one if its positive (6, 8)

3 0

3 years ago

Plz help!! Will give 30 points!!

Inessa [10]

Answer:

B) 12

Step-by-step explanation:

C is the circumference, d is the diameter, and r is the radius. They are related by the following equations:

d = 2r

C = πd = 2πr

If d = 6.0, then r = 3.0.

If C / C' = 0.25, then:

(2πr) / (2πr') = 0.25

r / r' = 0.25

3 / r' = 0.25

r' = 12

8 0

4 years ago

Read 2 more answers

Find the area of this shape please quick to.

erica [24]

First do (30×20)/2 + 20×25 + 35×42 + (42×25)/2
it should give you a total of 2795 cm

7 0

3 years ago

A researcher claims that the variation in the salaries of elementary school teachers is greater than the variation in the salari

guajiro [1.7K]

Answer:

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

$F_{critical} = 1.8608$

$F = 2.9085$

The decision rule is

Reject the null hypothesis

There is sufficient evidence to support the researchers claim

Step-by-step explanation:

From the question we are told that

The first sample size is $n_1 = 30$

The sample variance for elementary school is $s^2_1 = 8324$

The second sample size is $n_2 = 30$

The sample variance for the secondary school is $s^2_2 = 2862$

The significance level is $\alpha = 0.05$

The null hypothesis is $H_o : \sigma^2_1 = \sigma^2 _2$

The alternative hypothesis is $H_a : \sigma_1 ^2 > \sigma^2_2$

Generally from the F statistics table the critical value of $\alpha = 0.05$ at first and second degree of freedom $df_1 = n_1 - 1 = 30 - 1 = 29$ and $df_2 = n_2 - 1 = 30 - 1 = 29$ is