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Korvikt [17]
3 years ago
14

Bobby’s uncle gave him 300 baseball cards. Each week, Bobby purchases 40 baseball cards to add to his collection.

Mathematics
2 answers:
satela [25.4K]3 years ago
5 0

Answer:C

Step-by-step explanation:

Bobby’s uncle gave him 300 baseball cards. Each week, Bobby purchases 40 baseball cards to add to his collection.

Which inequality can be used to find w, the number of weeks after starting his collection when Bobby will have more than 700 baseball cards in his collection?

A) 300w + 40 > 700

B) 300w + 40 < 700

C) 40w + 300 > 700

D) 40w + 300 < 700

Julli [10]3 years ago
4 0

Answer:

C

Step-by-step explanation:

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A farmer has a field in the shape of a triangle. The farmer has asked the manufacturing class at your school to build a metal fe
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Answer:

<em>Fencing required = 1586 m</em>

Step-by-step explanation:

The given statements can be thought of a triangle \triangle ABC as shown in the diagram attached.

A be the 1st vertex, B be the 2nd vertex and C be the 3rd vertex.

Distance between 1st and 2nd vertex, AB = 435 m

Distance between 2nd and 3rd vertex, AC = 656 m

\angle A =49^\circ

To find:

Fencing required for the triangular field.

Solution:

Here, we know two sides of a triangle and the angle between them.

To find the fencing or perimeter of the triangle, we need the third side.

Let us use <em>Cosine Rule </em>to find the third side.

Formula for cosine rule:

cos A = \dfrac{b^{2}+c^{2}-a^{2}}{2bc}

Where  

a is the side opposite to \angle A

b is the side opposite to \angle B

c is the side opposite to \angle C

\Rightarrow cos 49^\circ = \dfrac{656^{2}+435^{2}-BC^{2}}{2\times 435\times 656}\\\Rightarrow BC^2 = 430336+189225-2 (435)(656)cos49^\circ\\\Rightarrow BC^2 = 430336+189225-570720\times cos49^\circ\\\Rightarrow BC^2 =619561-570720\times cos49^\circ\\\Rightarrow BC \approx 495\ m

Perimeter of the triangle = Sum of three sides = AB + BC + AC

Perimeter of the triangle = 435 + 495 + 656 = <em>1586 m</em>

<em></em>

<em>Fencing required = 1586 m</em>

4 0
3 years ago
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\displaystyle\int_{-\infty}^\infty f(x)\,\mathrm dx=\int_0^2cx^{1/2}\,\mathrm dx=\dfrac{2c}3x^{3/2}\bigg|_{x=0}^{x=2}=\dfrac{2^{5/2}c}3=1

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c=\dfrac3{2^{5/2}}=\dfrac3{4\sqrt2}
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Which of the following accurately pairs the part of an atom to its charge ?
rusak2 [61]
Electron—negative charge

Happy studying ^_^
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The cost of holding a children's birthday party at a rollerskating rink is a function of n, the number of people in the party. T
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