Which expression shows the sum of the polynomials with like terms grouped together? (8x+3z-8z^2)+(4y-5z)

There were 26 people at Charlotte and Oliver's birthday party. The total cost of the party was $1,429.74. How much did each pers

Nutka1998 [239]

Answer:

$54.99/person

Step-by-step explanation:

Divide '26 persons' into the total cost $1,429.74: we get $54.99/person.

3 0

3 years ago

The heights of 40 randomly chosen men are measured and found to follow a normal distribution. An average height of 175 cm is obt

AVprozaik [17]

Answer:

95% two-sided confidence interval for the true mean heights of men is [168.8 cm , 181.2 cm].

Step-by-step explanation:

We are given that the heights of 40 randomly chosen men are measured and found to follow a normal distribution.

An average height of 175 cm is obtained. The standard deviation of men's heights is 20 cm.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average height = 175 cm

$\sigma$ = population standard deviation = 20 cm

n = sample of men = 40

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } }$ ]

= [ $175-1.96 \times }{\frac{20}{\sqrt{40} } }$ , $175+1.96 \times }{\frac{20}{\sqrt{40} } }$ ]

= [168.8 cm , 181.2 cm]

Therefore, 95% confidence interval for the true mean height of men is [168.8 cm , 181.2 cm].

The interpretation of the above interval is that we are 95% confident that the true mean height of men will be between 168.8 cm and 181.2 cm.

3 0

3 years ago

Plzzzzzzzz help right answer gets brainly

rusak2 [61]

Answer:

20

Step-by-step explanation:

6 0

4 years ago

Read 2 more answers

In the jone school library,10/20 of the computers have scanners.in simplest form, which fraction of the computers have scanners?

n200080 [17]

Answer:

1/2

Step-by-step explanation:

5 0

3 years ago

You have $44000 in a savings account that pays 2% annual interestand the inflatation rate is 3.24%. How much buying power in dol

puteri [66]

At the end of the year ...
the price will be 44,000*1.0324 = 45,425.60
the bank balance will be 44,000*1.02 = 44,880.00

This is 545.60 fewer dollars than required to pay the price.

You lose $545.60 in current-year buying power.

4 0

3 years ago