Answer:
The price now is 300$.
Step-by-step explanation:
The problem is related to percentages.
It is provided that the price of meal at a restaurant a couple of decades (20 years) ago was 100$.
Now the price is 200% more than what it was 20 years ago,i.e. the price increased by 200%.
Compute the new price as follows:
![New-Price=100\$+[100\$\times200\%]\\= 100\$+[100\times\frac{200}{100}]\$\\ =100\$+200\$\\=300\$](https://tex.z-dn.net/?f=New-Price%3D100%5C%24%2B%5B100%5C%24%5Ctimes200%5C%25%5D%5C%5C%3D%20100%5C%24%2B%5B100%5Ctimes%5Cfrac%7B200%7D%7B100%7D%5D%5C%24%5C%5C%20%3D100%5C%24%2B200%5C%24%5C%5C%3D300%5C%24)
Thus, the price of the meal now is 300$.
ight what do i gotta answer tho
Answer:
option (B) 20
Step-by-step explanation:
Data provided in the question:
Number of photographs initially sold = 20
selling price of first 20 photographs = $10 each
Therefore,
Revenue from 20 photographs = 20 × $10 = $200
Selling price of further photographs = $15
Let the number of additional photographs sold be 'x'
thus,
total revenue = $200 + $15x
now,
according to the question
80% of ($200 + $15x) = $400
or
0.80 × ($200 + $15x) = $400
or
($200 + $15x) = $500
or
$15x = $300
or
x = 20
Hence,
the answer is option (B) 20
Answer:
The answer is number 1 because if you put it into a calculator correctly you'll get 10
Answer:
Im pretty sure this is the answer.
