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Dima020 [189]
3 years ago
8

What is the radical form of the square root of 1450?

Mathematics
1 answer:
dalvyx [7]3 years ago
3 0
\sqrt{1450} =   \sqrt{25*58} = 5\sqrt{58}
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(x^2+4)^2−11(x^2+4)+24=0<br>find one solution for this equation
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Answer:

Step-by-step explanation:

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Can anybody help me with this? <br> This question is confusing and I don't get it.
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Part B
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