We find the answer by using the density formula: d =m/v
We know the density: 0.1785
We know the volume: 3,249
We DO NOT know the mass, so that is what we're trying to finding
0.1785 = m/3,249
Solve:
3,249 * 0.1785 = m/3,249 * 3,249
579.9465 which can be rounded to 579.9
The answer is D.
It’s 200 dollars for 25 years
Answer:
q = 6; r = 7
Step-by-step explanation:
Answer:
1.7m
Step-by-step explanation:
Given that 'm' was the waiting time before the outbreak
After the outbreak, waiting time increased by 70%.
This implies that :
70% of m increase
m + 70% of m
m + 70/100 of m
m + ( 70÷100 ) × m
m + 0.7m
= 1.7m
The volume of the region R bounded by the x-axis is: 
<h3>What is the volume of the solid (R) on the X-axis?</h3>
If the axis of revolution is the boundary of the plane region and the cross-sections are parallel to the line of revolution, we may use the polar coordinate approach to calculate the volume of the solid.
From the given graph:
The given straight line passes through two points (0,0) and (2,8). Thus, the equation of the straight line becomes:

here:
- (x₁, y₁) and (x₂, y₂) are two points on the straight line
Suppose we assign (x₁, y₁) = (0, 0) and (x₂, y₂) = (2, 8) from the graph, we have:

y = 4x
Now, our region bounded by the three lines are:
Similarly, the change in polar coordinates is:
where;
- x² + y² = r² and dA = rdrdθ
Therefore;
- rsinθ = 0 i.e. r = 0 or θ = 0
- rcosθ = 2 i.e. r = 2/cosθ
- rsinθ = 4(rcosθ) ⇒ tan θ = 4; θ = tan⁻¹ (4)
- ⇒ r = 0 to r = 2/cosθ
- θ = 0 to θ = tan⁻¹ (4)
Then:


Learn more about the determining the volume of solids bounded by region R here:
brainly.com/question/14393123
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