Answer:
19 seconds.
Step-by-step explanation:
Given that the clock was exactly on time at 7am, and at 1pm the clock was 228 seconds late, to determine, at that rate, how slow was the clock half an hour, the following calculation must be performed:
1 PM = 13:00
13 - 7 = 6
228/6 = 38
38/2 = 19
Thus, every half hour the clock is delayed 19 seconds.
Let
be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time
is given by

and its height is

where
is 9.8 m/s^2, the magnitude of the acceleration due to gravity.
The time it takes for the cat to hit the ground is
with

(Unfortunately, this doesn't match any of the given options...)
The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed
was

(Again, not one of the answer choices...)
I'm guessing there's either a typo in the question or answers.
Answer:
y = -8x² + 8x + 48
Step-by-step explanation:
y= −4(x−3)(2x+4)
y = -8x² + 8x + 48
Answer:
x=10, y=6
Step-by-step explanation:
the send equation minus the first.
(5x+y)-(3x+y)=56-36
2x=20--->x=10
then put x=10 to the first equation, 3*10+y=36, get y=6
Answer:
sorry if im not this certain person but i would say( -1,-3)
Step-by-step explanation: