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oksano4ka [1.4K]
3 years ago
5

What is the length of the unknown leg in the right triangle?

Mathematics
2 answers:
OLEGan [10]3 years ago
7 0

Answer:

<h2>The leg missing is 15 meters long.</h2>

Step-by-step explanation:

We know that one leg of the triangle is 20 meters long, the hypothenuse is 25 meters long, and the leg missing is called <em>b</em>.

To solve this problem, we need to use Pythagorean's Theorem

25^{2}=20^{2}+b^{2}\\ b=\sqrt{25^{2}-20^{2}}\\ b=\sqrt{625-400} =\sqrt{225}\\ b=15

Therefore, the leg missing is 15 meters long.

Rama09 [41]3 years ago
3 0

Answer:

we will use Pythagorean's Theorem

25^{2}=20^{2}+b^{2}\\\\ b=\sqrt{25^{2}-20^{2}}\\\\ b=\sqrt{625-400} =\sqrt{225}\\\\ b=15

Therefore, the missing leg is  15 meters long.

Step-by-step explanation:

we will use pythagoras theorem

Given that,

One leg of the triangle is 20 meters long,

the hypothenuse is 25 meters long,

and the leg missing is called x.

we will use Pythagorean's Theorem

25^{2}=20^{2}+b^{2}\\\\ b=\sqrt{25^{2}-20^{2}}\\\\ b=\sqrt{625-400} =\sqrt{225}\\\\ b=15

Therefore, the missing leg is  15 meters long.

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The first digit of a string of 2002 digits is a 1. Any two-digit number formed by consecutive digits within this string is divis
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The largest possible last digit in the string of 2002 digits and number divisible by 19 or 31 is 9.

Given the first digit of a string of 2002 digits is 1 and the two digit number formed by consecutive digits within the string is divisible by 19 or 31.

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Hence the largest possible last digit and number divisible by 19 or 31 in this string is 9.

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