Answer:
2 stickers will be left over
Step-by-step explanation:
To answer the question, all you need to do is figure out at what value of stickers would the remaining stickers be equal to 2 if the piles are made up of either 3 to a set or 4 to a set. To do this, we need to figure out the size of the whole set of stickers.
Lets assume that the total number of stickers is 14. Lets test the 2 given conditions. If we divide it in piles of 3 then we will have a pile of 12 stickers (4 piles of 3 stickers each) with 2 stickers remaining.
Lets test the second condition. If we divide it in piles of 4, we will again have 12 stickers (3 piles of 4 stickers each) with 2 stickers remaining.
Now that both conditions have been satisfied, all we have to do is see how many stickers are left if we make a pile of 12 stickers. In this case, we will have just one pile of 12 stickers and, again, we will be left with 2 stickers.
Therefore, the answer is 2 stickers
Answer:
- 1296 pounds per square inch
Step-by-step explanation:
<u>Direct variation equation:</u>
<u>In this case it is:</u>
- y = kx², where y- strength, x- depth of the beam, k- coefficient
<u>Substitute the given values and solve for k:</u>
- 3600 = k*10²
- 3600 = 100k
- k = 3600/100
- k = 36
<u>The equation becomes:</u>
<u>Now, find the value of y, when x is 6:</u>
<u><em>Note, I took the depth as 6 inches but the question is a bit confusing by saying "four six inches". If it is 4 inches then your answer will be:</em></u>
Answer:
This person have a 29 % probability to receive a speeding ticket
Step-by-step explanation:
The probability of receive a speeding ticket in one of the traps is equal to the probability of going through that trap during the operation time of the trap.
Like we have four traps, and the probabilities are independent, then the probability of receive a speed ticket in one of them, is the sum of the probability for each trap.
P=P1+P2+P3+P4
The probability of going through a trap during the operation time is obtained by multiplying the probability of passing through the trap by the frequency of operation
Frequency of operation:
TL1 ⇒ 40 % = 0.4
TL2 ⇒ 30 % = 0.3
TL3 ⇒ 20 % = 0.2
TL4 ⇒ 30 % = 0.3
Probability of passing through these locations
PL1 ⇒ 0.3
PL2 ⇒ 0.2
PL3 ⇒ 0.4
PL4 ⇒ 0.1
then,
P1= TL1*PL1
P2= TL2*PL2
P3= TL3*PL3
P4= TL4*PL4
and
P = TL1*PL1 + TL2*PL2 + TL3*PL3 + TL4*PL4 = 0.12 + 0.06 + 0.08 + 0.03 = 0.29 = 29 %
This person have a 29 % probability to receive a speeding ticket
Answer:
138 pounds
Step-by-step explanation:
Let the required weight of the patient be x pounds.
We have that,
156 milligrams of medicine is required for a patient weighing 104 pounds.
Then, 207 milligrams of medicine will be required for a patient having weight as shown below,
Weight of the patient = 
i.e. x = 
i.e. x = 
Hence, the patient needing 207 milligrams of medicine will have the weight 138 pounds.
Answer:
Okay so basically your going to distribute the first equation where it says 4(2x+1) which gives you 8x+4.As you can see that is one of the answers on the right of it so then you go and answer the next problem 3(y+2) ect.If ya need help I can help you too?
