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3 years ago

6

Can someone please help me

2 answers:

skad [1K]3 years ago

8 0

C. Adding 18 to both sides isolates the variable term.

Your end goal is to isolate “x” which is a variable. However, the variable is multiplied by 6 and is “6x” making it a variable term. You must first isolate the variable term before you can isolate the variable itself. So step 1 is to add 18 to both sides (cancelling it out on the left side of the equals sign), thus isolating the variable term.

Ann [662]3 years ago

4 0

Answer:

C. Adding 18 to both sides isolates the variable term

Step-by-step explanation:

We can get rid of A and C because we can clearly see that we are adding, not subtracting.

The reason why C is correct is because we are isolating 6x, the term, and not <em>x</em>, the variable.

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3 years ago

Which is one solution of the following system <br> 2y-2x=12 <br> x^2+y^2+36

Olenka [21]

Answer:

Given the system of equations:

$2y-2x =12$ .....[1]

$x^2+y^2=36$ .....[2]

We can write equation [1] as;

2(y-x) = 12

Divide both sides by 2 we get;

$y-x = 6$

or

y = x+6 ....[3]

Substitute equation [3] in [2] we get;

$x^2+(x+6)^2=36$

$x^2+x^2+36+12x=36$

Subtract 36 from both sides we have;

$x^2+x^2+12x=0$

Combine like terms;

$2x^2+12x =0$

or

$2x(x+6)=0$

By zero product property:

x =0 and x+6 = 0

or

x = 0 and x = -6

now, substitute the given values of x in [3] we have;

for x = 0

y = 0+6 = 6

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y = -6 + 6 = 0

Therefore, the solution for the given system of equation is, either (0, 6) or (-6, 0)

7 0

3 years ago