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maksim [4K]
3 years ago
14

The fish tank at Matthew's house holds 468 gallons but is leaking at a rate of 4 gallons per day. Ariana's fish tank holds 624 g

allons but is leaking at a rate of 7 gallons per day. After how many days will the amount of water in the two tanks be the same?
Mathematics
1 answer:
user100 [1]3 years ago
6 0
468 plus 624 times 7 divided by 4 and you should get the amount of water in the two tanks
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2 years ago
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A trapezoid has bases that measure 10cm and 6cm. The height of the figure is 15cm. What is the area of the trapezoid?
kati45 [8]
Hello!

To find the area of a trapezoid you use the equation

A = \frac{a+b}{2} h

A is area
h is height
a and b are the bases

Put in the values we know

A =  \frac{10+6}{2} *15

Add

A =  \frac{16}{2} *15

Divide

A = 8 * 15

Multiply

A = 120

The answer is 120cm squared

Hope this helps!
8 0
3 years ago
Fill in the blanks using a variable or variables to rewrite the given statement. Is there an integer that has a remainder of 2 w
likoan [24]

Answer:

Step-by-step explanation:

Yes, integers like 27,57,87,117,.... and so on gives a remainder of 2 when it is divided by 5 and a remainder of 3 when it is divided by 6.

6 0
3 years ago
A notebook has a perimeter of 36 inches and an area of 80 square inches. What are the dimensions of the notebook?
maw [93]
Let L be length and W be width
The perimeter of a rectangle is 2W+2L=36
Thus 2W=36-2L, W=18-L
Area of a rectangle is WL=80
Thus (18-L)(L)=80
18L-L^2=80
L^2-18L+80=0
(L-8)(L-10)
Thus L can either be 8 or 10.
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4 0
3 years ago
The proportion of defective computers built by Byte Computer Corporation is 0.15. In an attempt to lower the defective rate, the
FinnZ [79.3K]

Answer:

a)<em> Null hypothesis : H₀</em>:  the proportion of defective item of computer has been lowered. That is P < 0.15

<u><em>Alternative hypothesis: H₁:</em></u> The proportion of defective item of computer

has been higher. That is P> 0.15 (Right tailed test)

b)    Test statistic   Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }

c)     Calculate the value of the test statistic = 0.991

d) The critical value at 0.01 level of significance = Z₀.₀₁ = 2.57

e) Null hypothesis accepted at 0.01 level of significance

f) we accepted null hypothesis.

  Hence t<em>he proportion of defective item of computer has been lowered. </em>

Step-by-step explanation:

<u>Step(i)</u>:-

<em>Given the sample size 'n' = 42</em>

Given random sample of 42 computers were tested revealing a total of 4 defective computers.

The defective computers 'x' = 4

<em>The sample proportion of defective computers </em>

                                                                p = \frac{x}{n} = \frac{4}{42} = 0.095

<em>Given The Population proportion 'P' = 0.15</em>

<em>The level of significance ∝=0.01</em>

<u>Step(ii)</u>:-

a)<em> Null hypothesis : H₀</em>:  the proportion of defective item of computer has been lowered. That is P < 0.15

<u><em>Alternative hypothesis: H₁:</em></u> The proportion of defective item of computer

has been higher. That is P> 0.15 (Right tailed test)

b)

    Test statistic   Z = \frac{p-P}{\sqrt{\frac{PQ}{n} } }

                       

c)      

                 Z = \frac{0.095-0.15}{\sqrt{\frac{0.15(0.85)}{42} } }

                 z = \frac{-0.055}{\sqrt{0.00303} } = - 0.9991      

                     

  Calculate the value of the test statistic Z = - 0.9991

                                   |Z| = |- 0.9991| = 0.991

<u>Step(iii)</u>:-

d)

        The critical value at 0.01 level of significance = Z₀.₀₁ = 2.57

e)   Calculate the value of the test statistic Z = 0.991 < 2.57  at 0.01 level of significance.

<u><em>Conclusion</em></u>:-

    Hence the null hypothesis is accepted at 0.01 level of significance.

f)

<em>     The proportion of defective item of computer has been lowered.</em>

 

6 0
3 years ago
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