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GalinKa [24]
3 years ago
6

Add the given polynomials. 3x^2 – 3x – 2 and -4x^2+ 6x – 2

Mathematics
1 answer:
tia_tia [17]3 years ago
7 0

Answer:

-4x^2+6x-2

Step-by-step explanation:

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Chipper had 189 hits in 572 at bats calculate chippers batting average for season by dividing the number if hits by the number o
lord [1]

Answer:

0.330

Step-by-step explanation:

Divide the number of hits (189) by the number of bats (572)

189/572=0.330

8 0
4 years ago
What position did Theodore Roosevelt hold before he became president?
BlackZzzverrR [31]

Answer:

He served as Assistant Secretary of the Navy under President William McKinley

hope i helped

-lvr

3 0
3 years ago
It’s not C and I suck at math can someone plz help me on this plz and thx
Fittoniya [83]

Answer:

a

Step-by-step explanation:

The volume (V) of a cone is calculated as

V = πr²h ( r is the base radius and h the perpendicular height )

To calculate the height h use the right triangle formed by the radius and the inclined side.

Given diameter = 22, then r = 22 ÷ 2 = 11 cm

Using Pythagoras' identity on the right triangle, then

h² + 11² = 61² , that is

h² + 121 = 3721 ( subtract 121 from both sides )

h² = 3600 ( take the square root of both sides )

h = \sqrt{3600} = 60

Thus

V = π × 11² × 60

   = 3.14 × 121 × 60 ≈ 22796.4 cm³ → a

7 0
3 years ago
5x + 2y = 6 3x + y = 4 Which of the following is part of the solution to the system of equations?
BabaBlast [244]
5x + 2y = 6
3x + y = 4....multiply by -2
-------------
5x + 2y = 6
-6x - 2y = -8 (result of multiplying by -2)
-------------add
-x = -2
x = 2

5x + 2y = 6
5(2) + 2y = 6
10 + 2y = 6
2y = 6 - 10
2y = -4
y = -4/2
y = -2 <=== here it is
6 0
4 years ago
Read 2 more answers
Question<br> (X-5y/y3)-1=
Ilia_Sergeevich [38]

Answer:

x  = y^3+5y

Step-by-step explanation:

Complete question

\frac{x - 5y}{y^3} - 1=0\\

Required

Solve for x

We have:

\frac{x - 5y}{y^3} - 1=0

Collect like terms

\frac{x - 5y}{y^3} = 1

Multiply through by y^3

x - 5y = y^3

Make x the subject

x  = y^3+5y

8 0
3 years ago
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