The vertex of this parabola is at (-1,-3) which of the following could be its equation

2 answers:

6 0

Since these are parabolas with y being squared, the standard form of such a parabola with vertex at (h, k) is

x = a(y - k)^2 + h 

There are no steps. Just look at what is inside the parentheses and compare it to (y - k) with k = -3. 
Then look at what is added and compare it to h = -1. 

For instance, A has (y + 1) in parentheses. So k = -1. And it has -3 added, so h = -3. That would be a vertex at (-3, -1).

inn [45]3 years ago

3 0

For
y=a(x-h)^2+k
vertex is (h,k)

it could be
y=a(x+1)^2-3

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Answer:

A) $\frac{1}{5}$

B) - 5

C) Not Possible

D) 5

E) $\frac{-1}{5}$

Step-by-step explanation:

All integers are rational numbers. But not all rational numbers are integers.

All whole numbers are integers. But not all integers are whole numbers.

I am a rational number but not an integer. Located on the right of 0.

This means that it should be a positive number. Since, it is a rational number but not an integer, it should be of the form $\frac{p}{q}$ .

From, the options $\frac{1}{5}$ would fit this description.

I am a rational number and an integer but not a whole number.

This means that it should be a negative integer. Since, all positive integers and zero would be whole numbers. From the options, the answer would be -5.

I am a whole number but not an integer.

This is clearly not possible because all whole numbers are a subset of integers.

I am a rational number, a whole number and an integer.

This means it is a positive integer. 5 would fit this description.

I am a rational number but not an integer; located on the left side of 0.

This means it is a negative number. $-\frac{1}{5}$ should be the answer.