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EleoNora [17]
3 years ago
15

Given a regular octagon, in how many ways can we color one diagonal red and another diagonal blue so that the two colored diagon

als cross (in the interior)? Consider rotations and reflections distinct.
Mathematics
1 answer:
Zina [86]3 years ago
7 0

Answer:

Rotation = 1.

Reflection = 5 or 4.

Step-by-step explanation:

A regular octagon is the octagon that has eight, 8 sides and all these eight sides are equal.

So, if we are going to consider rotation and reflection distinct in order to color one diagonal red and another diagonal blue so that the two colored diagonals cross (in the interior) we can do that by following the steps Below;

=> Make sure that the first diagonal with the red color is drawn first.

=> to another make fixing to another end.

=> Determine the possibilities.

The numbers of times can be gotten by using Burnside Lemma which gives Rotation = 1 And Reflection = 5 or 4.

You might be interested in
Loook below find the area
sweet-ann [11.9K]

Step-by-step explanation:

step 1. this is a trapezoid. the area A = (b1 + b2)h/2 where b1 is the bottom base and b2 is the top base (per se), and h is the height. this formula is the definition of the area of a trapezoid.

step 2. A = (b1 + b2)h/2 = (22 + 9)(5)/2

step 3. A = 31(5)/2 = 155/2 = 77.5in^2.

5 0
2 years ago
What’s the answer to this algebra question
natka813 [3]

Answer:

x=9, x=7

Aka x= 9,7

Step-by-step explanation:

Oh goodie, factoring.

I used to be very good at this. My memory is a LITTLE rusty but let's see if we can bust out some penzoil and fix my aching joints (yes I just stole the quote from that terrible show, sue me), shall we?

1. x^2 - 11x + 68 = 5x +5

2. Chuck all the x variables to the left: x^2 - 16x + 68 = 5

3. Get rid of that pesky loser, 5, by subtracting from both sides of the equation (Note that it's important to remember LIKE TERMS, don't try subtracting 5 from 16x, you'll hurt yourself): x^2 - 16x + 68 - 5 = 5 - 5

New equation: x^2 - 16x + 63 = zilch (0)

4. Use AC method to factor: x2+bx+c. AC method definition: a pair of numbers whose product is c and whose sum is b: (x-9)(x-7)=0

5. Solve for x.

Booyah.

4 0
3 years ago
Two sisters, sister A and sister B, play SCRABBLE with each other every evening. Sister A is a statistician, and she draws a ran
snow_tiger [21]

Answer:

First question: LCL = 522, UCL = 1000.5

Second question: A sample size no smaller than 418 is needed.

Step-by-step explanation:

First question:

Lower bound:

0.36 of 1450. So

0.36*1450 = 522

Upper bound:

0.69 of 1450. So

0.69*1450 = 1000.5

LCL = 522, UCL = 1000.5

Second question:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

The project manager believes that p will turn out to be approximately 0.11.

This means that \pi = 0.11

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The project manager wants to estimate the proportion to within 0.03

This means that the sample size needed is given by n, and n is found when M = 0.03. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.11*0.89}{n}}

0.03\sqrt{n} = 1.96\sqrt{0.11*0.89}

\sqrt{n} = \frac{1.96\sqrt{0.11*0.89}}{0.03}

(\sqrt{n})^2 = (\frac{1.96\sqrt{0.11*0.89}}{0.03})^2

n = 417.9

Rounding up

A sample size no smaller than 418 is needed.

6 0
3 years ago
Can someone help please.
Kryger [21]
Graph A is the correct answer tell me if you need a step by step explanation

8 0
3 years ago
Read 2 more answers
With a certain tail wind a jet aircraft arrives at its destination, 1,890 miles away, in 3 hours. Flying against the same wind,
Gelneren [198K]
<span>Find the wind speed and the plane's airspeed.
:
Let s = speed of the plane in still air
Let w = speed of the wind
then
(s-w) = plane speed against the wind
and
(s+w) = plane speed with the wind
:
Change 3 3/8 hrs to 3.375 hrs
:
The trips there and back are equal distance, (1890 mi) write two distance equations
dist = time * speed
:
3.375(s-w) = 1890
3.0(s + w) = 1890

:
It is convenient that we can simplify both these equations:
divide the 1st by 3.375
divide the 2nd by 3
resulting in two simple equations that can be used for elimination of w
s - w = 560
s + w = 630
----------------adding eliminates w, find s
2s = 1190
s = 
s = 595 mph is the plane speed in still air
Find w
595 + w = 630
w = 630 - 595
w = 35 mph is the wind spee</span>
3 0
3 years ago
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