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barxatty [35]
4 years ago
15

Thirty-six students at a large university were given a test to measure their intelligence quotient (IQ). A histogram of the IQ t

est scores is shown below. In each interval, the left endpoint is included in the interval, but not the right endpoint. A histogram titled I Q Scores has I Q score on the x-axis and frequency on the y-axis. 93 to 96, 1; 96 to 99, 3; 99 to 102, 5; 102 to 105, 8; 105 to 108, 2; 108 to 111, 7; 111 to 114, 7; 114 to 117, 2; 117 to 120, 1. In which interval is the median located?
Mathematics
1 answer:
Verizon [17]4 years ago
7 0

Answer:

102-105

Step-by-step explanation:

Median formula for a group data is expressed as shown;

Median = (N+1)/2 th value/interval

N is the total number of students

From the question N = 36

Median = (36+1)/2

Median = 37/2

Median = 18.5

Therefore we are to cumulate the value of the frequency up till the 18.5th value.

From the table

If we keep cummulating the frequency from the top;

Let's add:

1+3+5+5+8 = 21

Since the 18.5th values falls within the cumulative frequency value (i.e 21), the corresponding interval where we stopped cumulating will be our Median.

From the table, the interval with the frequency of 8 is 102 - 105. Hence the median is located at the interval 102 - 105

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telo118 [61]

<u>Given</u>:

Given that the irregular figure is broken into a triangle and a rectangle.

We need to determine the length b, the area of the triangle , the area of the rectangle and the area of the irregular figure.

<u>Length of b:</u>

The length of b , the base of the triangle is given by

b=5-(2\frac{1}{3})

Simplifying, we get;

b=5-\frac{7}{3}

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Thus, the length of the base of the triangle is \frac{8}{3} \ ft

<u>Area of the triangle:</u>

The area of the triangle can be determined using the formula,

A=\frac{1}{2}bh

Substituting b=\frac{8}{3} \ ft and h=3 \ ft, we get;

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<u>Area of the rectangle:</u>

The area of the rectangle can be determined using the formula,

A=lw

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A=5 \times \frac{4}{3}

A=\frac{20}{3} \ ft^2

Thus, the area of the rectangle is \frac{20}{3} \ ft^2

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The area of the irregular figure can be determined by adding the area of the triangle and the area of the rectangle.

Thus, we have;

Area = Area of the triangle + Area of the rectangle

Substituting the values, we have;

Area = 4+\frac{20}{3}

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