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natulia [17]
3 years ago
10

PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!

Mathematics
1 answer:
Harrizon [31]3 years ago
3 0
180-53 is 127 angle 6 and 3 would be the same so your answer is 127
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15 chocolate were distributed between raju and sanju in the ratio 2:3 . How many chocolates did raju receive?​
Elodia [21]

Answer:

6chocolates

Step-by-step explanation:

Given

The total number of chocolate = 15chocolates

If it is divide into ratio 2:3

total ratio = 2+3

Total ratio = 5

Number of chocolate raju receives = 2/5 * 15

Number of chocolate raju receives = 2 * 3

Number of chocolate raju receives = 6chocolates

6 0
3 years ago
A carpenter charges $45 for every 50 feet of fence he builds plus a travel charge of $37.50. If the equation, C = 4550F + 37.5 ,
Tju [1.3M]

Answer:

Step-by-step explanation:

Given the total cost of the building expressed as;

C = 4550F + 37.5

C is the total cost

F is the length of the fence

Given

C = $352.50

Required

The length of the fence F

Substitute into the formula;

C = 4550F + 37.5

$352.50 =  4550F + 37.5

4550F = 352.50 - 36.5

4550F =  316

F = 316/4550

F = 0.0695 feet

hence 0.0695 feet of fence will cost $352.50

4 0
3 years ago
Find the limit<br> Picture below
pogonyaev

Answer:

a. 4

Step-by-step explanation:

We want to find;

\lim_{h \to 0} \frac{f(2+h)-f(2)}{h}

If f(x)=x^2.

f(2+h)=(2+h)^2

f(2+h)=4+4h+h^2

Also;

f(2)=2^2

f(2)=4

This implies that;

\lim_{h \to 0} \frac{4+4h+h^2-4}{h}

Simplify;

\lim_{h \to 0} \frac{4h+h^2}{h}

Factor to get;

\lim_{h \to 0} \frac{h(4+h)}{h}

Cancel the common factors.

\lim_{h \to 0} 4+h

Substitute h=0 to get

\lim_{h \to 0} 4+h=4+0=4

7 0
4 years ago
Read 2 more answers
15.437 rounded to the nearest hundredth is it 16.43
azamat
If you would like to know how much is 15.437 rounded to the nearest hundredth, you can calculate this using the following steps:

Rounded number to the nearest hundredth would be <span>15.44.

The correct result would be 15.44 and not 16.43.</span>
7 0
3 years ago
Read 2 more answers
∠1 and​ ​ ∠2 ​ ​are complementary angles.
nika2105 [10]

Answer:

23

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
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