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Karolina [17]
3 years ago
6

60 and 108 The GCF IS​

Mathematics
2 answers:
Ahat [919]3 years ago
5 0

<em>Answer:</em>

<em>Greatest common factor (GCF) of 60: 223</em>

<em>Greatest common factor (GCF) of 108: 22333</em>

<em>The Greatest Common Factor (GCF) is:   2 x 2 x 3 = 12</em>

<em>Step-by-step explanation:</em>

<em>To get the Greatest Common Factor (GCF) of 60 and 108 we need to factor each value first and then we choose all the copies of factors and multiply them.</em>

<em></em>

CaHeK987 [17]3 years ago
3 0
The greatest common divisor of these numbers is 12.
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3 years ago
Which sentence matches the mathematical equation? p-0.40p=0.60p
IRISSAK [1]
P-0.40p = 0.60p

C. Decrease by 40% is the same as multiply by 60%.

Assume that p = 10

10 - 0.40(10) = 0.60(10)
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Based on the above assumption. 40% of 10 is 4 ; and 60% of 10 is 6. So, 10 less 4(40% of 10) is equal to 6 (60% of 10). 

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7 0
3 years ago
A manufacturer produces bearings, but because of variability in the production process, not all of the bearings have the same di
Lena [83]

Answer:

Proportion of all bearings falls in the acceptable range = 0.9973 or 99.73% .

Step-by-step explanation:

We are given that the diameters have a normal distribution with a mean of 1.3 centimeters (cm) and a standard deviation of 0.01 cm i.e.;

Mean, \mu = 1.3 cm            and           Standard deviation, \sigma = 0.01 cm

Also, since distribution is normal;

                 Z = \frac{X -\mu}{\sigma} ~ N(0,1)

Let X = range of diameters

So, P(1.27 < X < 1.33) = P(X < 1.33) - P(X <=1.27)

  P(X < 1.33) = P( \frac{X -\mu}{\sigma} < \frac{1.33 -1.3}{0.01} ) = P(Z < 3) = 0.99865

  P(X <= 1.27) = P( \frac{X -\mu}{\sigma} < \frac{1.27 -1.3}{0.01} ) = P(Z < -3) = 1 - P(Z < 3) = 1 - 0.99865

                                                                                            = 0.00135

 P(1.27 < X < 1.33) = 0.99865 - 0.00135 = 0.9973 .

Therefore, proportion of all bearings that falls in this acceptable range is 99.73% .

7 0
3 years ago
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